1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddik [55]
3 years ago
12

Solve for x algebraically:

Mathematics
1 answer:
Masja [62]3 years ago
5 0
<span>THE GIVEN QUESTION; 7x -3(4x-8) < 6x +12 - 9x THE GIVEN INTERVAL OF X IS FROM [4,8] SO THE VALUE OF X ={4,5,6,7,8} THE GIVEN QUESTION CAN BE EVALUATED TO 7x - 12x+ 24 < 12 - 3x -5x + 24 < 12 - 3x //USING BODMAS RULE NOW SUBSTITUTING THE VALUE OF X: 1) X=4 SOL: 4<0 2) X=5 SOL: -1<-3 3) X=6 SOL: -6<-6 4) X=7 SOL: -11<-9 5) X=8 SOL: -16<-12 HENCE THE VALUE OF X=7,8 SATISFY THE GIVEN INEQUALITY</span>
You might be interested in
-x-4(x-2)<br> Help please
Keith_Richards [23]

Answer:

-5x+8

Step-by-step explanation:

7 0
2 years ago
Twice the sum of a number p and 3.
Korvikt [17]

Answer:

7

Step-by-step explanation:

no explanation needed the answer is in the question

4 0
3 years ago
Please I’m confused…
Anika [276]

Answer:

I believe it should be

4 : 1 : 200

Step-by-step explanation:

4 0
2 years ago
The amount that households pay service providers for access to the Internet varies quite a bit, but the mean monthly fee is $50
Natali5045456 [20]

Answer:

(a) See Explanation

(b) \bar x =50 and \sigma_x = 0.8944

(c) The shape is normal

(d) P(\bar x > 55) = 0

Step-by-step explanation:

Given

\mu = \$50 -- mean

\sigma = \$20 --- standard deviation

n=500 --- sample size

Solving (a): The reason we can't determine the probability that an amount to access internet by a household will exceed $55.

The question says that a lot of households pay low rates, but the percentage of the households in this category is not given. This means that it is impossible to determine the shape of the distribution.

Hence, the probability cannot be calculated.

Solving (b): Sample mean and Sample standard deviation

The sample mean estimates the population mean

So:

\bar x =\mu

\bar x =50

The sample standard deviation is calculated as thus:

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{20}{\sqrt{500}}

\sigma_x = \frac{20}{22.36}

\sigma_x = 0.8944

Solving (c): The shape of the distribution.

We have:

n = 500 --- The sample size

According to Central limit theorem, When the sample size is greater than 30, then the shape of the distribution is normal.

<em>Hence, the shape is normal</em>

Solving (d): P(\bar x \ge 55)

Calculate the test statistic (t)

t = \frac{\bar x - \mu}{\sigma}

t = \frac{55 - 50}{0.8945}

t = \frac{5}{0.8945}

t = 5.590

So:

P(\bar x > 55) = P(t > 5.590)

Referencing the z table, we have:

P(t > 5.590) = 0

Hence:

P(\bar x > 55) = 0

5 0
3 years ago
What is the equation of a line that passes through (1,2) and has a slope of 7?
Paraphin [41]
ANSWER: y=7x-5 i put it in a graphing calculator
3 0
3 years ago
Other questions:
  • The table represents a linear equation. Which equation shows how (–10, 8) can be used to write the equation of this line in poin
    14·1 answer
  • a chocolate chip cookie has 10 more calories than an ice cream cone. together they have a total of 310 calories.
    12·1 answer
  • Find the equation of the line with slope = -6 and passing through (-6,32).write your equation
    12·1 answer
  • One fourth of a number is 12 find the number​
    15·2 answers
  • I will Rate you 5 stars and give you 30 points
    15·1 answer
  • Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
    10·1 answer
  • Select the three statements below that are true about quarts and cups.
    11·2 answers
  • Let f be defined by the function f(x) = 1/(x^2+9)
    13·1 answer
  • Jose invested $5,100 in an account paying an interest rate of 8 % compounded
    7·1 answer
  • Help please <br><br> 9 2 7 <br> X = 12 x 12
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!