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3 years ago

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Approximate 278 to the nearest tenth.

t{278} " alt=" \sqrt{278} " align="absmiddle" class="latex-formula">

1 answer:

ohaa [14]3 years ago

8 0

Answer:

well 278 rounded to the nearest 10 is 280 idk how to round a whole number to the nearest 10th

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Solve for W: P=2L + 2W<br><br>A. W=P-L<br>B. W= 1/2P - L<br>C. W= 1/2 P + L<br>D. W= 2P - L

svetlana [45]

Answer:

B

Step-by-step explanation:

$P=2L+2W$

$P-2L=2W$ (Subtract 2L from both sides of the equation)

$2W=P-2L$ (Symmetric Property of Equality)

$W=\frac{P-2L}{2}$ (Divide both sides of the equation by 2)

$W=\frac{P}{2} -\frac{2L}{2}$ ("Split" the fractions)

$W=\frac{1}{2}P-L$ (Simplify)

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GuDViN [60]

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2 years ago

gabriel put 6000 in a 2 year CD paying 4% interest, compounded monthly. After 2 years , he withdrew all his money. what was the

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3 years ago

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Simplify the following expression as much as possible. 4^10/4^10 x 7^0=?

kap26 [50]

Answer:

1

Step-by-step explanation:

4^10/4^10 x 7^0 =

= 4^(10 - 10) * 1

= 4^0 * 1

= 1 * 1

= 1

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3 years ago

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What are the coordinates of the vertex of the parabola with the equation y = x + 2x - 3?

loris [4]

Answer:

<em>The coordinates of the vertex are (-1,-4).</em>

Step-by-step explanation:

<u>Equation of the Quadratic Function </u>

The vertex form of the quadratic function has the following equation:

$y-k=a(x-h)^2$

Where (h, k) is the vertex of the parabola that results when plotting the function, and a is a coefficient different from zero.

We are given the function:

$y=x^2+2x-3$

We must transform the equation above by completing squares:

The first two terms can be completed to be the square of a binomial. Recall the identity:

$x^2+2xy+y^2=(x+y)^2$

Thus if we add and subtract 1:

$y=(x^2+2x+1)-3-1$

Operating:

$y=(x^2+2x+1)-4$

The trinomial in parentheses is a perfect square:

$y=(x+1)^2-4$

Adding 4:

$y+4=(x+1)^2$

Comparing with the vertex form of the quadratic function, we have the vertex (-1,-4).

The coordinates of the vertex are (-1,-4).

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2 years ago