two trains leave towns 480 km apart at the same time and travel toward each other. one train travels 18 km/h faster than the oth

er. If they meet in 2 hours what is the rate of each train?

Mathematics

1 answer:

KonstantinChe [14]1 year ago

3 0

$\begin{gathered} \text{Let assume one train spe}ed\text{ is x km/h} \\ \text{Second train spe}ed\text{ is }\Rightarrow(x+18)\text{ km/h} \\ \text{They m}eet\text{ in 2 hour,so} \\ 2=\frac{480}{x+x+18} \\ 2x+18=\frac{480}{2} \\ 2x=240-18 \\ x=\frac{222}{2} \\ x=111\text{ km/h (1st train spe}ed) \\ x+18=111+18=129\text{ km/hr (2nd rain sp}eed)\text{ } \end{gathered}$

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What's the lateral area of a right cylinder if the radius of the base is 12mm and the altitude of the cylinder is 5 times the ba

gizmo_the_mogwai [7]

Answer:

1440π squared mm.

Step-by-step explanation:

Given is the radius of base of cylinder, r = 12mm.

The altitude is five times the base radius, h = 5 times 12mm = 60mm.

The lateral area of the cylinder is the curved surface area of the cylinder.

The formula for curved surface area of cylinder is as follows:-

Curved Surface Area = Circumference of base x altitude of cylinder.

SA = 2πrh = 2π•12•60 = 1440π sq. mm.