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3 years ago

13

Write forty and eight tenths as a decimal. 48.1 40.8 40.08 40.008

2 answers:

Amiraneli [1.4K]3 years ago

8 0

What we already know is that we have a 40. Eight tenths would look like the following: .8
This is because it says 8 tenths, meaning the 8 is in the tenths place, right after the decimal. So, the answer would be 40.8

tankabanditka [31]3 years ago

4 0

Fourty and eight tenths as a decimals is 40.8. More than one pounds behind decimal is too much and a different number other than 8 is wrong. The answer is B: 40.8.

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The complete solution is

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Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

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The auxiliary equation is

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$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

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