Meeeee I have a question that I need help on please check it out and try to help me
Answer:
4 cm
Step-by-step explanation:
The perimeter of the original rectangle is ...
P = 2(L+W) = 2(4x + x) = 10x
The perimeter of the larger rectangle after we add "a" to each side is ...
P = 2(L +W)
= 2((4x+a) +(x+a))
= 10x +4a = 10x +16
4a = 16 . . . . . subtract 10x from both sides
a = 4 . . . . . . . divide by 4
The length added to each side is 4 cm.
Answer:

Step-by-step explanation:
The width of rectangle is the diameter of the semi-circle part
Area of one semicircle is given by 
Total area of semi circle will be 
Substituting 74 m for d and
as 3.14 we obtain
Total area semi-circle=
Area of rectangle is given by the product of length and width
Rectangular area=
Total area of rectangular and semi-circles will be

Therefore, area of training field is 
A1/27 = A2/39 =>
A2 = A1*39/27
A2 = 711×39/27
A2 = 1027 m^2