Write the equation of the circle centered at (0,1) with radius 15.

Mathematics

1 answer:

NNADVOKAT [17]2 years ago

6 0

Answer:

$x^2+(y-1)^2=225$

Step-by-step explanation:

we know that

The equation of the circle in center radius form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

$(h,k)=(0,1)\\r=15\ units$

substitute

$(x-0)^2+(y-1)^2=15^2$

$x^2+(y-1)^2=225$

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Describe the slope of the line<br> Find the slope

Dmitry_Shevchenko [17]

Answer:

Question one: Zero slope
Question two: $m=\frac{0}{4}$

Step-by-step explanation:

Given the following questions:

<u>Question one:

</u>The following line is what you call a "zero slope." Zero slopes are lines that are neither decreasing or increasing and remain at a constant or just a straight line.

Question two:

Point A = (-2, -3) = (x1, y1)
Point B = (2, -3) = (x2, y2)

Using the formula for slope or rise over run we will solve and find the slope of this line.

$m=\frac{y2-y1}{x2-x1}$
$m=\frac{-3--3}{2--2} =\frac{0}{4}$
$m=\frac{0}{4}$

The slope of this line is "0/4."

Hope this helps.