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Montano1993 [528]
1 year ago
11

A basket contains six apples and four peaches. You randomly select one piece of fruit and eat it. Then you randomly select anoth

er piece of fruit. The first piece of fruit is an apple and the second piece is a peach. Find the probability of this occuring.A. 4/15B. 1/4C. 1/6D. 15/56
Mathematics
1 answer:
Margarita [4]1 year ago
3 0

6 apples + 4 peaches = 10 pieces of fruit

First choice is an apple = 6 /10 = 3/5

Now, there are:

5 apples + 4 peaches = 9 pieces of fruit

Second choice is a peach = 4 /9

Multiply the 2 fractions:

3/5 x 4/9 = 12/45 = 4/15

Answer= 4/15 (A)

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The statement tan theta -12/5, csc theta -13/12, and the terminal point determined by theta is in quadrant 2."
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3 years ago
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An automobile insurance company divides customers into three categories: good risks, medium risks, and poor risks. Assume that o
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Answer:

0.60

Step-by-step explanation:

Probability that the customer is not a poor risk = 1 - probability that the customer is a poor risk

Firstly, let’s calculate the probability of being a poor risk.

From the given data the number of poor risks = 14229-7362-1190 = 5677

So the probability of being a poor risk = 5677/14229 = 0.399

Thus, the probability that the customer is not a poor risk = 1-0.399 = 0.601 which to 2 decimal places = 0.60

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Identify the slope (m) and y-intercept (b) of each linear equation.<br> 52. 3x+4y=24
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Answer:

Step-by-step explanation:

  [1]    3x - 4y = -24

  [2]    -x - 16y = -52

Graphic Representation of the Equations :

   -4y + 3x = -24        -16y - x = -52  

 

Solve by Substitution :

// Solve equation [2] for the variable  x

 [2]    x = -16y + 52

// Plug this in for variable  x  in equation [1]

  [1]    3•(-16y+52) - 4y = -24

  [1]     - 52y = -180

// Solve equation [1] for the variable  y

  [1]    52y = 180

  [1]    y = 45/13

// By now we know this much :

   x = -16y+52

   y = 45/13

// Use the  y  value to solve for  x

   x = -16(45/13)+52 = -44/13

Solution :

{x,y} = {-44/13,45/13}

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