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Zepler [3.9K]
1 year ago
5

A 3,162-kg truck moving with a velocity of 12 m/s to the East hits a 510-kg parked car. The impact causes the car to be set in m

otion at 24 m/s East. What is the velocity of the truck immediately after the collision?
Physics
1 answer:
Musya8 [376]1 year ago
6 0

Given:

The mass of the truck is m1 = 3162 kg

The speed of the truck is v1i = 12 m/s in East

The mass of the parked car is m2 = 510 kg

The speed of car is v2i = 0 m/s

The speed of car after collision is v2f = 24 m/s in East

To find the speed of the truck after collision.

Explanation:

The final velocity of the truck will be

\begin{gathered} m1v1i+m2v2i=m1v1f+m2v2f \\ v1f\text{ =}\frac{m1v1i-m2v2f+m2v2i}{m1} \\ =\frac{3162\times12-510\times24+510\times0}{3162} \\ =8.129\text{ m/s} \end{gathered}

Thus, the speed of the truck after collision is 8.129 m/s

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False

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The volume of the gas is 7.6\cdot 10^{-4}m^3

Explanation:

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In this problem, we have an amount of moles of gas of

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Since 1 mol of gas occupies a volume of 22.4 L, we can set up the following ratio:

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What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
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The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

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F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

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