Answer:
Therefore the answer is the precision in the speed DECREASES
Explanation:
In quantum mechanics, we have the uncertainty principle that establishes that when the accuracy of the position increases the accuracy the speed decreases, being related by the expression
Δx Δv ≥ h'/ 2
h' = h/2π
Therefore the answer is the precision in the speed DECREASES
Answer:

I dont the child mass...you should substitute that value to (m)
then you can get your answer
The correct answer is D: which is none of the above.
Hint: a wreckling ball contains pontential energy that acts like a pendulum
a pot of water contains pontential thermal energy
We consider the momentum in the x-direction and apply the principle of conservation of momentum to form the equation:
m(A)u(A) = m(A)v(A) + m(B)v(B), since u(B) = 0 as B is at rest
We calculate v(A) using:
Vx = Vcos∅
Vx = 2.1cos(30)
Vx = 1.82 m/s
1.5 x 4.5 = 1.5 x 1.82 + 3.2v(B)
v(B) = 1.26 m/s
The deflection angle of B will be 30° above the positive x-axis, so:
v(B) = Vcos∅
V = 1.26 / cos(30)
V = 1.45 m/s
The velocity of B is 1.45 m/s
If the rocket it heavy and tall the distance wouldn't go very far but if the rocket was little and had no weight on it, it would go farther than the heavier one because of density/mass in the rocket