Question

What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C test charge placed here?

Answer 1

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Electric field on the master charge

E = kq/r²

where;

• q is magnitude of master charge
• r is distance of separation
• k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

Force on the test charge

F = Eq

where;

• E is electric field
• q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

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