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4 years ago

Is 2/3 an improper fraction or a mixed number

2 answers:

7 0

It's neither.
If it were to be an improper fraction, it would be something like 3/2 instead of 2/3.
If it were to be a mixed number, it would look like 1 1/3.

algol134 years ago

4 0

Hey!

QUICK REVIEW

In order for a fraction to be improper, the numerator must be greater than the denominator. In order for a fraction to be a mixed number, there must be a whole number and a fraction.

END QUICK REVIEW

The fraction 2 over 3 is not an improper fraction, nor is it a mixed number.

Hope this helps!

- Lindsey Frazier ♥

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Help please due soon

ANEK [815]

Answer: c=24

Step-by-step explanation: 15×3=45. 8×3=24. Just multiply both the numerator and denominator by 3.

5 0

3 years ago

Read 2 more answers

NEED HELP

blagie [28]

Answer:

Range: [-7, 8]

General Formulas and Concepts:

Algebra I

Reading a coordinate plane
Range is the set of y-values that are outputted by function f(x)
Interval Notation: [Brackets] denote inclusion, (Parenthesis) denote exclusion

Step-by-step explanation:

According to the graph, our y-values span from -7 to 8. Since both are closed dot, they are included in the range:

Range: [-7, 8]

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3 years ago

What is 2. 314 (3.14 repeating )as a fraction

soldier1979 [14.2K]

Your final answer will be 2 157/500 for the decimal 2.314

8 0

3 years ago

Ricardo has a square hot tub. He wants to build a square pool next to it that is a dilation of the hot tub using a scale factor

ozzi

Answer:

$\boxed{Side \ Length \ of \ hot \ tub = 4.8\ ft.}$

Step-by-step explanation:

Scale Factor = 5

Also,

B'C' = 24 feet

Since both are squares so both have all sides equal.

Sqaure A'B'C'D' is dilated by a scale factor of 5

So,

AB = BC = CD = DA = 24/5 = 4.8 ft.

4 0

4 years ago

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0

3 years ago