Answer:
Proved with RHS congruency rule.
Step-by-step explanation:
Given ΔEAB and ΔDCB are two right triangles. The figure has ∠BED≅ ∠BDE. Point B is the midpoint of segment AC.
We have to prove that ΔEAB ≅ ΔDCB
In ΔEAB and ΔDCB
BE=BD (∵∠BED≅ ∠BDE)
AB=BC (given B mid-point)
By RHS congruency rule which states that two right triangles are congruent if the hypotenuse and one side of triangle are respectively equal to the hypotenuse and the corresponding side of the other triangle.
Hence, By RHS rule
ΔEAB ≅ ΔDCB
Hence Proved.
Answer:
120
Step-by-step explanation:
Because you would just multiply the 2 numbers which would get you the area.
OH right! I should have realised that!
S6 = 7,812 = a1 * (5^6 - 1)
----------- were a1 = first term
5 - 1
3906*a1 = 7812
a1 = 7812 / 3906 = 2
Therfore the second term = 2*5 = 10 Answer
Answer:
a) 1/2
b) 1/n
c) 1/4
Step-by-step explanation:
a) For each permutation, either 1 precedes 2 or 2 precedes 1. For each permutation in which 1 precedes 2, we can swap 1 and 2 to obtain a permutation in which 2 preceds 1. Thus, half of the total permutations will involve in 1 preceding 2, hence, the probability for a permutation having 1 before 2 is 1/2.
c) If 2 is at the start of the permutation, then it is impossible for 1 to be before 2. If that is not the case, then 1 has a probability of 1/n-1 to be exactly in the position before 2. We can divide in 2 cases using the theorem of total probability,
P( 1 immediately preceds 2) = P (1 immediately precedes 2 | 2 is at position 1) * P(2 is at position 1) + P(1 immediately precedes 2 | 2 is not at position 1) * P(2 is not at position 1) = 0 * 1/n + (1/n-1)*(n-1/n) = 1/n.
d) We can divide the total of permutations in 4 different groups with equal cardinality:
- Those in which n precedes 1 and n-1 precedes 2
- those in which n precedes 1 and 2 precedes n-1
- those in which 1 precedes n and n-1 precedes 2
- those in which 1 precedes n and 2 precedes n-1
All this groups have equal cardinality because we can obtain any element from one group from another by making a permutations between 1 and n and/or 2 and n-1.
This means that the total amount of favourable cases (elements of the first group) are a quarter of the total, hence, the probability of the event is 1/4.
The area of a triangle formal is base times height divided by 2. So 9x 12 which equals 108 then you divide that by 2 which equals 54 and the unit is cm^2
