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Elza [17]
1 year ago
6

Figure 4 shows part of the curve with equation

Mathematics
1 answer:
swat321 year ago
7 0

The values of a and b are 2 and π/5, respectively

<h3>How to determine the values of a and b?</h3>

The graph of the complete question is added as an attachment

The equation of the graph is given as:

y = sin(ax - b)

From the graph, we have the following points:

(π/10, 0), (3π/5, 0) and (11π/10, 0)

Substitute the above points in y = sin(ax - b)

sin(a(π/10) - b) = 0 and sin(a(3π/5) - b) = 0

Take the arc sin of both sides

a(π/10) - b = 0

a(3π/5) - b = π

Subtract the equations to eliminate b

a(π/10) - a(3π/5) = -π

Divide through by π

a(1/10) - a(3/5) = -1

Express fractions as decimals

0.1a - 0.6a = -1

Evaluate the difference

-0.5a = -1

Divide by -0.5

a = 2

Substitute a = 2 in a(3π/5) - b = π

2 * (3π/5) - b = π

Evaluate the product

6π/5 - b = π

This gives

b = 6π/5 - π

Evaluate the difference

b = π/5

Hence, the values of a and b are 2 and π/5, respectively

Read more about sine functions at:

brainly.com/question/9565966

#SPJ1

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The length of a rectangle is 4 m less than the diagonal and the width is 5 m less than the diagonal. If the area is 82 m^2, how
nikklg [1K]

I hate rounding.

Let's call the diagonal x.  It's the hypotenuse of the right triangle whose legs are the rectangle sides.

According to the problem we have a length x-4 and a width x-5 and an area

82 = (x-4)(x-5)

82 = x^2 - 9x + 20

0 = x^2 - 9x - 62

That one doesn't seem to factor so we go to the quadratic formula

x = \frac 1 2(9 \pm \sqrt{9^2-4(62)}) = \frac 1 2(9 \pm \sqrt{329})

Only the positive value makes any sense for this problem, so we conclude

x = \frac 1 2(9 \pm \sqrt{329})

That's the exact answer.  Did I mention I hate rounding?  That's about

x = 13.6 meters

Answer: 13.6

----------

It's not clear to me this problem is consistent.  By the Pythagorean Theorem the diagonal satisfies

x^2 = (x-4)^2 + (x-5)^2

which works out to

x=9 \pm 2\sqrt{10}

That's not consistent with the first answer; this problem really has no solution.  Tell your teacher to get better material.

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A family visits a car show to research information on vehicles they might consider purchasing. Brochures for each vehicle provid
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Answer:

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Step-by-step explanation:

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