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Stells [14]
3 years ago
13

Help Me Solve This

Mathematics
1 answer:
olasank [31]3 years ago
3 0
Let us assume the number of cd's you can buy = x
Cost of an used CD = $4.25
Total amount of money that you have = $1500
Then
<span>x ≤ 15 − 4.25
</span>x ≤  10.75

I hope the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.
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Ms.Holmes decided to water her plants.She had 2 1/2 gallons of water.She gave each plant 1/4 gallon of water.Which expression co
Inessa [10]

Answer:

(1/4)x=2 1/2

Step-by-step explanation:

It is 2.5 gal. of water and 0.25 gal. of water per plant.

It could also be x=(1/4)/(2 1/2)

6 0
3 years ago
Guys Pls Help ASAP! Will Give Brainliesttt. <br><br> Thxx
Allisa [31]

Answer:

23. x= -2/5 x= -5

24. x= 3/4 x= -1/6

25. x= 7/3. x= -5/4

26. x= 3 x= -2/3

27. x= 1. x= -2/7

28. x= 9/4. x= -1/3

29. x= 2/5 x= 1/3

30. x= 2/3 x= 1/2

6 0
3 years ago
Select all the correct answers.
vlabodo [156]
Car load and insurance premium
7 0
3 years ago
Read 2 more answers
Kyle asked a random group of students what their favorite sport was. The results are below. Boys Girls Basketball 10 8 Football
Ronch [10]

Answer:

The probability that Kyle will pick a girl who likes football is 12.5%.

Step-by-step explanation:

The data provided is as follows:

                         Boys        Girls       Total

Basketball          10             8             18

 Football           25             7             32

  Soccer             9             19             28

 Baseball           18            22            40

   Total               62           56            118

Compute the probability that Kyle will pick a girl who likes football as follows:

P(F|G)=\frac{n(G\cap F)}{n(G)}

            =\frac{7}{56}\\\\=0.125\\\\=12.5\%

Thus, the probability that Kyle will pick a girl who likes football is 12.5%.

6 0
3 years ago
Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data
tresset_1 [31]

Based on the information represented by the boxplot ;

  • Latasha's lowest sale amount = 50

  • Kayla's median is between 200 and 300

  • Latasha has a greater spread due to higher IQR value

1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>

  • The minimum value is denoted by the starting position of the lower whisker on a boxplot.

  • Lowest amount of sale made by Latasha = 50

2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>

  • 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

  • 50% of sales made by Kayla is between 200 and 300

  • With median sale value being 250

3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>

  • The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

  • IQR = Upper Quartile (Q3) - Lower quartile(Q1)

<u>For Latasha</u> :

  • Q3 = 450 (Endpoint of the box)
  • Q1 = 150 (starting point of the box)

  • IQR = 450 - 150 = 300

<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>

  • Q3 = 375 (Endpoint of the box)
  • Q1 = 100 (starting point of the box)
  • IQR = 375 - 100 = 275

  • Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0
2 years ago
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