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1 year ago

Y = 2/7xfind slopey-interceptis it proportional?Please Help

Mathematics

1 answer:

Drupady [299]1 year ago

6 0

$\begin{gathered} y=\frac{2}{7}x \\ \text{slope}=\frac{2}{7} \\ y-\text{intercept}=0 \\ \end{gathered}$

The variables are proportional. The constant of proportionality is 2/7.

Note slope intercept equation is

y = mx + b

where

m = slope

b = y-intercept

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3 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

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3 years ago

2x + 2y = 2, 2(x + y) = 10}

Dima020 [189]

X will equal 5
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4 years ago

A sample of carbon dioxide occupies a volume of 3.50 l at 125 kpa pressure. what pressure would the gas exert if the volume was

Novosadov [1.4K]

The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.

Ideal gas behavior:

Suppose the initial volume of carbon dioxide gas is V = 3.5l

Initial pressure is P = 125 kPa

Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L

The final pressure of the gas is P'.

We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.

PV = P'V'

125 × 3.5 = P'× 2

P'= 218.75 kPa

Therefore, the final pressure is 218.5 kPa.

Learn more about ideal gas, visit brainly.com/question/11676583?referrer=searchResults

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AlexFokin [52]

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3 years ago

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