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3 years ago

Point Q is on line segment PR. Given QR=11 and PQ=3, determine the length PR.

Mathematics

2 answers:

klio [65]3 years ago

3 0

Answer:

$\huge \boxed{14}$

Step-by-step explanation:

Q is a point on the line segment PR.

PQ = 3

QR = 11

PR = PQ + QR

PR = 3 + 11 = 14

Anna11 [10]3 years ago

3 0

Answer:

$\huge\boxed{PR = 14}$

Step-by-step explanation:

QR = 11

PQ = 3

Given that Q is on line segmant PR

So,

PR = PQ + QR

PR = 3 + 11

PR = 14

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ACD is a triangle and B is a point on AC. AB = 8cm and BC is 6cm. Angle BCD = 48° and angle BDC = 50°. (a) Find the length of BD

FromTheMoon [43]

Answer:

5.8206 cm
10.528 cm
23.056 cm^2

Step-by-step explanation:

(a) The Law of Sines can be used to find BD.

BD/sin(48°) = BD/sin(50°)

BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm

(b) We can use the Law of Cosines to find AD.

AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°

AD^2 ≈ 110.841

AD ≈ √110.841 ≈ 10.5281 . . . cm

(c) The area of ∆ABD can be found using the formula ...

A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°

A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2

_____

Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.

5 0

3 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

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3 years ago

What is go math grade 8 lesson 9.1 page 279 answers?

lana [24]

The answers are online or you can use an app to scan it to give answers

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3 years ago

Which of the following statements best describes the solution to the problem below?

ZanzabumX [31]

Answer:

Step-by-step explanation:

Using rule of negatives and positives:
The rules for multiplication and division are simple: If both numbers are positive, the result is positive. If both numbers are negative, the result is positive. If one number is positive and the other is negative, the result is negative.

This is why C is the correct statement

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2 years ago

Please answer this correctly without making mistakes

boyakko [2]

Answer:

105/4 or 26.25 mi

Step-by-step explanation:

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fairfax to yardley = 17 3/8 = 139/8

71/8 + 139/8 = 105/4 or 26 2/8

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