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tiny-mole [99]
1 year ago
13

Find a solution to the linear equation −2x−2y=8 by filling in the boxes with a valid value of x and y.Provide your answer below:

−2( )−2(. )=8
Mathematics
1 answer:
inna [77]1 year ago
6 0

Given

-2x-2y=8

To find a solution for the linear equation, the first step is to write the equation in slope-intercept form:

-Pass the x-term to the right side of the equation by applying the opposite operation to both sides of the equal sign:

\begin{gathered} -2x+2x-2y=8+2x \\ -2y=2x+8 \end{gathered}

-Divide both sides by -2:

\begin{gathered} \frac{-2y}{-2}=\frac{2x}{-2}+\frac{8}{-2} \\ y=-x-4 \end{gathered}

Once you have expressed the equation of the line in slope-intercept form, replace it with any value for x and calculate the corresponding value of y, for example, x=2

\begin{gathered} y=-(2)-4 \\ y=-2-4 \\ y=-6 \end{gathered}

One solution for the linear equation is x=2 and y=-6, you can check the solution by replacing the values on the original equation, with both values the result should be 8:

\begin{gathered} -2x-2y \\ -2\cdot2-2\cdot(-6) \\ -4+12=8 \end{gathered}

As you can see the values are a valid solution for the linear equation.

So the solution is:

-2(2)-2(-6)=8

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The point-slope form:

y-y_1=m(x-x_1)

We have:

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y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7


Notice: slope of -1 means that both f'(x_1), \ f'(x_2) are equal to -1, so f'(x_1)=-1 \ and \ f'(x_2)=-1


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