Answer:
Measure of angle 2 is 42.
If you are satisfied with the results then plz make me genius.
Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:
![A = 4\pi r^{2}](https://tex.z-dn.net/?f=A%20%3D%204%5Cpi%20r%5E%7B2%7D)
In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that ![\frac{dr}{dt} = 40](https://tex.z-dn.net/?f=%5Cfrac%7Bdr%7D%7Bdt%7D%20%3D%2040)
Determine the rate of change in surface area when r = 20 cm.
This is
when
. So
![A = 4\pi r^{2}](https://tex.z-dn.net/?f=A%20%3D%204%5Cpi%20r%5E%7B2%7D)
Applying implicit differentiation.
We have two variables, A and r, so:
![\frac{dA}{dt} = 8r\pi \frac{dr}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%208r%5Cpi%20%5Cfrac%7Bdr%7D%7Bdt%7D)
![\frac{dA}{dt} = 8*20\pi*40](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%208%2A20%5Cpi%2A40)
![\frac{dA}{dt} = 20106.19](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%20%3D%2020106.19)
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Answer:
first what you do is divide two and then for and then after you divide them together you can get your number so I'm going to show you example how to do it
Step-by-step explanation:
first divide 4 / 2 and then you can get your answer after you divide that