Answer:
7sq rt = 2.6457513110645907 = sqrt y^3
Step-by-step explanation:
Answer:
Step-by-step explanation:
The first step is to multiply the numbers of the numerator. Thus:
Writing the answer above as the product of a whole number and unit fraction (that is, mixed number), 5 goes in 8 1 time remainder 3. Therefore:
7.1(6)+4.8(6)= 71.4 the answer is $71.4
Since we are given that the relationship between x and y
is linear. Therefore this means that the given equation takes the form of:
y = m x + b
where,
b is the y intercept of the equation
m is the slope of the equation
However we should take note that the slope m is directly
proportional to the coefficient of correlation. Since our coefficient of
correlation is negative, this only means that the value of y is decreasing with
increasing x, hence plot of y and x is descending with increasing x.
Furthermore, this also tells that for every 1 unit increase of x, there is a
0.75 units decrease of y.
Part A)
If f(x) - 3 is the new equation, it means there is a vertical translation of f(x) down 3 units. The y-intercept will decrease by 3 units. Areas of increasing on the function may be lessened as the function is being translated down 3 units. The areas of decrease will increase because the function is being translated down. End behaviour will not change from a translation as long as the function is continuous at each end, (not a finite function with end points). The evenness or oddness of f(x) will not change either.
Part B:
The y-intercept will be flipped horizontally about the x-axis and multiplied by 2. This will mean that if the y-intercept was positive, it will now be negative and vice versa. The increasing and decreasing regions of the graph will be flipped, so anywhere f(x) was positive will now be negative and vice versa. They will also be double what they were before because all values are multiplied by 2. The end behaviour will switch. If f(x) was from Quad1->Quad3 for example, it will now be Quad2->Quad4 because of the flip at the x-axis. The evenness and oddness of the function will not change seeing as the degree of f(x) is not affected.
