This math is just too much and makes little to no sense.
d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a

= a₁ + (n-1)d</h3><h3>• S

=

[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =

[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
The total area between the squares is of 24 units squared.
Step-by-step explanation:
Area of a square:
The area of a square of side length l is given by:

Area between figures:
The area between two figures is the area of the larger figure subtracted by the area of the smaller figure.
Larger square:
Square with side of length 7. So

Smaller square:
Square with side of length 5. So

What is the total area between the squares?

The total area between the squares is of 24 units squared.
Answer:
117 inches squared
Step-by-step explanation:
perimeter= 44 inches
L=W+4
44=w+w+(w+4)+(w+4)
44=4w+8
36=4w
9=width
9+4=13
width=9
Length=13
area=L*W
13*9=117