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3 years ago

16 cans of soda. Two-eights of the cans are sprite. How many Sprites?

Mathematics

1 answer:

AleksAgata [21]3 years ago

7 0

The answer is that there are 4 sprites. Because eight is half of sixteen so i add the numerator together and 2+2=4

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What is the value of x ?

Hatshy [7]

Answer:

The value of x will be 2.5

LY will be 9 while KH will be 7.5

Step-by-step explanation:

Hope This Helped

6 0

3 years ago

What is the value of x in the diagram? A circular pool with a diameter of 18 ft will have a uniform 4 ft concrete walkway poured

Lunna [17]

If you visualize the problem, there are two concentric circles, the pool, and the pool plus the walkway. So, we have to subtract the area of these two concentric circles to find the walkway.

Bigger circle: Pool plus walkway
----------------------------------
diameter = 18 + 4(2) -- this is because there is 2 ft of walkway at each far end
diameter = 26 ft
Area = pi*(26/2)^2
Area = 530.93 ft2

Smaller circle:pool
---------------------
diameter = 18 ft
Area = pi*(8/2)^2
Area = 50.27 ft2

Area of walkway
----------------
A = 530.93 - 50.27
A = 480.66 ft2

Then the cost would be
Cost = $4.25 * 480.66
Cost = $2,042.81

8 0

3 years ago

The x-coordinate of the plotted point is . The y-coordinate of the plotted point is .

solmaris [256]

X-coordinate: -.50
Y-coordinate: -.55

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3 years ago

Tamara's dosage of medication has recently decreased 20 milligrams per day. What is the total decrease in Tamara's medication at

Leviafan [203]

7x20 = 140 making that the total amount of decrease per week. Hope this helps!

6 0

4 years ago

Read 2 more answers

30 POINTS!! ASAP! PLS SHOW WORK

sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ cannot be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0

3 years ago