Reduce to the lowest terms by canceling -14/9 times -3/7
1 answer:
You might be interested in
If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem, 
and 
. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
Answer:
D
Step-by-step explanation:
a^2+b^2=c^2
7^2+9^2=C^2
49+81=c^2
=c
=c