Answer:
The range is all real numbers.
Step-by-step explanation:
I graphed the equation on the graph below to find the range. The range is all real numbers because the line never stops and it touches all possible y-values.
If this answer is correct, please make me Brainliest!
4
x
+
5
y
=
15
4
x
+
5
y
=
15
Solve for
y
y
.
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y
=
3
−
4
x
5
y
=
3
-
4
x
5
Rewrite in slope-intercept form.
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y
=
−
4
5
x
+
3
y
=
-
4
5
x
+
3
Use the slope-intercept form to find the slope and y-intercept.
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Slope:
−
4
5
-
4
5
y-intercept:
3
3
Any line can be graphed using two points. Select two
x
x
values, and plug them into the equation to find the corresponding
y
y
values.
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x
y
0
3
1
11
5
x y 0 3 1
11
5
Graph the line using the slope and the y-intercept, or the points.
Slope:
−
4
5
-
4
5
y-intercept:
3
3
x
y
0
3
1
11
5
x y 0 3 1
11
5
image of graph
Remember this! The equation that represents a proportional relationship, or a line, is y=kx, where k is the constant of proportionality.
Answer:
Yolanda will have a balance of $34,043.10 in 14 years.
Step-by-step explanation:
This is an Ordinary annuity question where you pick the hint from the equal and recurring monthly payment.
To find the Future value of Yolanda's savings after 14 years, use Future value of annuity formula FVA = ![\frac{PMT}{r}[1-(1+r)^{-t} ]\\](https://tex.z-dn.net/?f=%5Cfrac%7BPMT%7D%7Br%7D%5B1-%281%2Br%29%5E%7B-t%7D%20%5D%5C%5C)
PMT= recurring payment = $300
r = discount rate; monthly rate in this case = 6% / 12 =0.5% or 0.005 as a decimal.
t = total duration ; 14 *12 = 168 months
Next, plug in the numbers into the FVA formula;
FVA = ![\frac{300}{0.005} [ 1-(1+0.005)^{-168} ]](https://tex.z-dn.net/?f=%5Cfrac%7B300%7D%7B0.005%7D%20%5B%201-%281%2B0.005%29%5E%7B-168%7D%20%5D)
FVA = 60,000 * 0.5673849
FVA = 34,043.0969
Therefore, Yolanda will have a balance of $34,043.10 in 14 years
Answer: C. x = 4 and x = 6
Step-by-step explanation:
Zeros of a function would be the value of x when f(x) is 0.
Based on the given graph, the parabola has 2 locations where the y-value is 0 and the graph hits the x-axis.
The graph hits the x-axis at 4 and at 6.
