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Goryan [66]
2 years ago
6

Would this be correct?

Mathematics
1 answer:
nekit [7.7K]2 years ago
3 0

Answer:

Yes it is absolutely right.

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Find the unit rate kenny reads 5/8 pages in 2/3 minutes
Cerrena [4.2K]
.9375 pages / 1 minute

or 15/16 pages for every 16/16 minute.
4 0
3 years ago
(4,2);slope=3<br><br>help me out
ivolga24 [154]
We have a point and a slope, so let's use the point slope formula!

(y - y1) = m(x - x1)
where
x1=4
y1=2
and m=3

(y - 2) = 3(x - 4) \\ y - 2 = 3x - 12 \\ y = 3x - 10
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3 years ago
Does this graph represent a function? Why or why not?
Lunna [17]

Answer:

Step-by-step explanation:

B. Yes, because it passes the vertical line test, is the answer.

6 0
2 years ago
Given the arithmetic sequence an = 4 − 3(n − 1), what is the domain for n? All integers where n ≥ 1 All integers where n &gt; 1
krok68 [10]

All integers where n ≥ 1.

We have given that the sequence,

a_{n} =4-3(n-1)

We have to find the domain for n.

<h3>What is the meaning of arithmetic sequence?</h3>

Arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first.

That is, a_{n} =a+(n-1)d

where a = first term of sequence.

d =common difference.

n =number of terms which belongs to natural numbers

By  the definition of arithmetic sequence n starts with 1

Remember that,the natural number starts with 1

Now, in given sequence  for nth term

a_{n} =4-3(n-1)

The domain for n is All integers where n ≥ 1.

To learn more about the arithmetic sequence visit:

brainly.com/question/20118982

4 0
2 years ago
Show all work to multiply (6+square root -64)(3-square root -16)
Hunter-Best [27]

Answer:

50

Step-by-step explanation:

- 8i = √-64

8i + 6

- -4i = -√-16

-4i + 3

[8i + 6][-4i + 3] → FOIL

>> -32i² + [24i - 24i] + 18

↑ ↑

-1 0

>>> 32 + 18 = 50

Information on Imaginary Numbers

√-1 = i

-1 = i²

-i = i³

1 = i⁴ [And every other exponent that is a multiple of 4; this cycle then repeats itself every time you go up one number at a time]

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my You-Tube channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

7 0
2 years ago
Read 2 more answers
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