Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
Answer:
I think it might be 24.5
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Answer:
6.02775720469
Step-by-step explanation:
step one: double check with calculator pls :)
step two pls <u><em>brainliest </em></u>
Answer:
6. D.
7. F.
8. A.
9. B.
10. C.
Step-by-step explanation:
6. 9 + (12 - 10)
12 - 10 = 2
9 + 2 = 11
7. (20 - 15) x 2
20 - 15 = 5
5 x 2 = 10
8. 10 ÷ 5 + 7
10 ÷ 5 = 2
2 + 7 = 9
9. 6 + 2 x 3
2 x 3 = 6
6 + 6 = 12
10. (2 x 4) + 8
2 x 4 = 8
8 + 8 = 16
Let me know if this helps!