The slope of a line perpendicular to the line 6x + 8y = -128 is 4/3.
Given,
The equation of a line = 6x + 8y = -128
We have to convert this into standard form of linear equation, y = mx + b :
So,
6x + 8y = -128
Add -6x to both sides,
6x + 8y - 6x = -6x - 128
Now,
8y = -6x - 128
Divide 8 on both sides
8y/8 = (-6x - 128) / 8
We get,
y = -6/8x - 16
Here, this is in standard form of linear equation.
Here slope of line, m₁ = -6/8
We have to find the slope of line(m₂) which is perpendicular to the given line.
If the line is perpendicular, the slope(m₂) will be the negative reciprocal of the slope(m₁) of the given line.
That is,
Slope of line, (m₂)= -(m₁) = - (-8/6) = 8/6 = 4/3
That is, the slope of the line which is perpendicular to the given line is 4/3.
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