Answer:
0.1333 = 13.33% probability that bridge B was used.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Arrives home by 6 pm
Event B: Bridge B used.
Probability of arriving home by 6 pm:
75% of 1/3(Bridge A)
60% of 1/6(Bridge B)
80% of 1/2(Bridge C)
So

Probability of arriving home by 6 pm using Bridge B:
60% of 1/6. So

Find the probability that bridge B was used.

0.1333 = 13.33% probability that bridge B was used.
3/5 of 180 is 108
180-108=72
she would have 72$ left
The answer is 24.84 because 29.44-4.6 is 24.84
to double check you can add (after you subtract and get your answer) 24.84 and 4.6 and get 29.44
Answer: A
Explanation do Pythagorean theorem and find the third side. Then do adjacent/hypotenuse.
The correct answer is B.) 4