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1 year ago

So I don't understand how V = lwh (h).... the topic is literal equations.

Mathematics

1 answer:

Kruka [31]1 year ago

6 0

1) Solving in terms of h

V = lwh Divide both sides by h

$\begin{gathered} V\text{ = lwh} \\ \frac{V}{h}=\frac{lwh}{h} \\ \frac{V}{h}\text{ =}lw\text{ Cross multiply} \\ hlw=V\text{ Divide both sides by lw} \\ \frac{hlw}{lw}=\text{ }\frac{V}{lw} \\ h\text{ = }\frac{V}{lw} \end{gathered}$

So rearranging that equation we can find h, in terms of V, and l and w.

If we want to solve in terms of l, or w, we'll proceed similarly to isolate the variable we want on the left side, and the other terms on the right side.

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What kind of graph is this ? A. Positive B. Negative C. Zero D. Undefined

Goryan [66]

Answer:

This graph is D undefined

Step-by-step explanation:

D is the correct answer because its have a zero on the y axis if there is a zero on the x axis then it would of have been Zero.

8 0

3 years ago

Read 2 more answers

3. A person standing 3 feet away from the base of a lamp post casts a shadow 4 feet long. If the person is 6 feet tall and walks

german

Answer:

533.33 ft/min

Step-by-step explanation:

We are given that

x=3 feet

y=4 feet

Height of person,h=6 feet

$\frac{dx}{dt}=400 ft/min$

Triangle ABC and A'B'C are similar because all right triangles are similar

By using similarity property

$\frac{h'}{6}=\frac{7}{4}$

$h'=10.5 feet$

$x+y=3+4=7 feet$

$\frac{h'}{6}=\frac{x+y}{y}$

$\frac{10.5}{6}=\frac{x+y}{y}$

$10.5y=6x+6y$

$10.5y-6y=6x$

$4.5y=6x$

Differentiate w.r.t t

$4.5\frac{dy}{dt}=6\frac{dx}{dt}$

$\frac{dy}{dt}=\frac{6\times 400}{4.5}ft/min$

$\frac{dy}{dt}=533.33ft/min$

Hence, If the person is 6 feet tall and walks away from the lamp post at a speed of 400 feet per minute then his shadow moving at the rate 533.33 ft/min