1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luda [366]
3 years ago
10

Amir stands on a balcony and throws a ball to his dog, who is at ground level.

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer:

the answer is 3.

Step-by-step explanation:

The ball's height is modeled by a quadratic function, whose graph is a parabola.

The maximum height is reached at the vertex.

So in order to find when that happens, we need to find the vertex.

Find the zereos and then divide by 2.

 

Bumek [7]3 years ago
6 0

Answer:

16 meters

Step-by-step explanation:

The height function is given by:

h(x)=-(x+1)(x-7)\\h(x)=-(x^2+x-7x-7)\\h(x)=-x^2+6x+7

The value of x, in seconds, for which the derivate of the height function is zero, is the time at which the maximum height occurs:

\frac{dh(x)}{dx}= h'(x)=-2x+6=0\\x=3

For x = 3 seconds, the height is:

h(3)=-(3^2)+6*3+7\\h(3)=16\ m

The maximum height that the ball will reach is 16 meters.

You might be interested in
A deck of cards contains 52 different cards. A card is drawn at random. What
Vadim26 [7]

Answer:

1/2 ( or 0.5)

Step-by-step explanation:

13 Clubs / 13 Spades are black, total: 26

probability: 26 / 52 = 1/2

3 0
3 years ago
Find the value of x. <br><br> is this the correct answer?
IgorLugansk [536]

Step-by-step explanation:

what's the radius

need the radius

5 0
3 years ago
Simplify y+1&lt;3 please need help
Zepler [3.9K]
STEP-BY-STEP SOLUTION:

Let's first establish the inequality which we need to solve as displayed below:

y + 1 < 3

To begin with, we need to make ( y ) the subject by keeping it on the left-hand side of the inequality and placing all other numbers on the right-hand side of the equality as displayed below:

y + 1 < 3

y < 3 - 1

Then, we simply simplify / solve as displayed below:

y < 3 - 1

y < 2

ANSWER:

y < 2
4 0
3 years ago
What is m∠C?<br><br> Round the value to the nearest degree.
Elis [28]

Answer: m\angle C=53\°

Step-by-step explanation:

For this exercise you need to use the Inverse Trigonometric function arcsine, which is defined as the inverse function of the sine.

Then, to find an angle α, this is:

\alpha =arcsin(\frac{opposite}{hypotenuse})

In this case, you can identify that:

\alpha =m\angle C\\\\opposite=AB=36\ cm\\\\hypotenuse=AC=45\ cm

Then, substituting values into \alpha =arcsin(\frac{opposite}{hypotenuse}) and evaluating, you get that the measure of the angle "C" to the nearest degree, is:

m\angle C=arcsin(\frac{36\ cm}{45\ cm})\\\\m\angle C=53\°

5 0
3 years ago
Which quadratic equation has the roots -1+4i and -1-4i
AysviL [449]

Answer:

C

Step-by-step explanation:

Solve the quadratic in answer choice C using the quadratic formula:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}.

Here a=1, b=2, and c=17.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{-2+/-\sqrt{(-2)^2-4(1)(17)} }{2(1)}=\frac{-2+/-\sqrt{4-68}}{2)}

\frac{-2+/-\sqrt{-64} }{2}=\frac{-2+/-8i }{2}=-1+/- 4i


6 0
4 years ago
Other questions:
  • Draw a Venn diagram to illustrate this conditional: Cars are motor vehicles.
    14·1 answer
  • 28÷(11-7+3)×2 <br><br>how do you do this
    11·2 answers
  • 2/3m+a=a+r (solve for m)<br><br> please show work, thank you!!!
    6·2 answers
  • Please help me please and thank you
    15·1 answer
  • Solve fory:
    7·1 answer
  • (02.07)<br> Solve for x.<br> -ax + 3b &gt; 5
    5·1 answer
  • SOME ONE HELP PLEASE ILL MARK BRAINIEiST. AND I NEED TO KNOW THE PRICE OF ORANGES. WORTH A 100 POINTS&gt; AND PLEASE DONT WASTE
    11·1 answer
  • Please help on test
    13·1 answer
  • What is the mass of 18 crayons
    13·1 answer
  • Use the equation f(x)=0.003x²-0.083x+2.514. Predict the value for x+20 years.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!