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julsineya [31]
1 year ago
12

Solve please and thank you!

Mathematics
1 answer:
Leya [2.2K]1 year ago
6 0

Answer:

The terms are:  " <u>-70</u>"<u>,</u> <u> </u><u>8p</u> <u>,</u> and:  <u>" </u><u>-3z</u><u> </u>".
__________
The coefficients are " 8 "  and:  " -3 " .

__________
Explanation:

<u>Note</u>:  The text within this very question is an "expression"—and Not an equation.

Note that there are 3 (three) terms in total in this given expression:
 " -70 + 8p - 3x " ;

  → which are:  " -70 ", 8p, and:  " -3z ";

__________


A "coefficient"  is a number that is attached to a "variable" —which generally is listed before the [particular] variable—to indicate that the variable is multiplied by:  [that certain particular number, which is the "coefficient."

<u><em>Note</em></u>:  For the 3 (three) terms given in expression:

" -70 " —has "no coefficient" ;

    →  since:  it is Not considered as: "being multipled by any variable— whatsoever."   Rather,  this is merely a "negative number" and a    "negative integer"
__________
" 8p " — the coefficient is " 8 ";

    →  since this is considered a "variable' —"p" ;                                                                  

          multiplied by a number: " 8 ".

__________

" -3z " —The coefficient is  " -3 " ;

    →  since this is considered a 'variable' — "z" ;

          multiplied by a number:  " -3 ".

__________
The coefficients are:  " 8 "  and:  " -3 ";

__________

Hope these answers with explanations are helpful!

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zhenek [66]

Answer:

  \dfrac{y^{18}}{8x^{18}}

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

  (a^b)^c = a^(bc)

__

Your expression simplifies as follows:

  \left(\dfrac{10x^3y^{-2}}{5x^{-3}y^4}\right)^{-3}=(2x^{3-(-3)}y^{-2-4})^{-3}=(2x^6y^{-6})^{-3}\\\\=(2^{-3})x^{6(-3)}y^{(-6)(-3)}=\dfrac{1}{8}x^{-18}y^{18}\\\\=\boxed{\dfrac{y^{18}}{8x^{18}}}

6 0
4 years ago
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mina [271]

Answer:

Step-by-step explanation:

5c + 4f ≥ 200

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5 0
2 years ago
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Answer: area

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4 0
3 years ago
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Write the expression in standard form. 2/(2-15i)
Eva8 [605]
<h3>Answer:</h3>

d. 4/229 +30/229i

<h3>Explanation:</h3>

Multiply numerator and denominator by the conjuate of the denominator, then simplify.

\dfrac{2}{2-15i}=\dfrac{2}{(2-15i)}\cdot\dfrac{(2+15i)}{(2+15i)}=\dfrac{4+30i}{2^2-(15i)^2}\\\\=\dfrac{4+30i}{4+225}=\dfrac{4}{229}+\dfrac{30}{229}i

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John is curious how much money he can make in a month. He makes one penny on March 1st. He hopes to double the amount he makes e
KonstantinChe [14]

Answer:

£10,737,418.24

Step-by-step explanation:

<u>Every day amount doubles:</u>

  • March 1st = 1p= 2^0 p
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