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Alinara [238K]
4 years ago
5

Consider the linear function that is represented by the equation y = 2 x + 2 and the linear function that is represented by the

graph below.
Which statement is correct regarding their slopes and y-intercepts?

A. The function that is represented by the equation has a steeper slope and a greater y-intercept.

B. The function that is represented by the equation has a steeper slope, and the function that is represented by the graph has a greater y-intercept.

C. The function that is represented by the graph has a steeper slope, and the function that is represented by the equation has a greater y-intercept.

D. The function that is represented by the graph has a steeper slope and a greater y-intercept.

Mathematics
1 answer:
frutty [35]4 years ago
3 0

Answer:

C) the function represented by the graph has a steeper slope and the function represented by the equation has a larger y-intercept.

Step-by-step explanation:

The equation is written in slope-intercept form, y=mx+b.  m is the slope and b is the y-intercept.  In this function, the slope is 2 and the y-intercept is 2.

Looking at the graph, the y-intercept is 1.  Going from the y-intercept, if we go up 2, it does not go over quite 1 unit.  Therefore the slope is steeper on the graph.

Hope I helped answer the question:)

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Two ships leave the same port in different directions, forming a 120° angle between them. One ship travels 70 mi. and the other
kondaur [170]

Answer : Distance between the ships to the nearest miles = 106.03 ≈ 106 mi.

Explanation :

Since we have shown in the figure below :

a=70 mi.

b=52 mi.

c=x mi.

\text{Since two ships leaves the same port in different directions forming a }120\textdegree\text{angle between them.}

So, we use the cosine rule , which states that

 c^2=a^2+b^2-2ab.cosC\\\\x^2=70^2+52^2-2\times 70\times 52\times cos(120\textdegree)\\\\x^2=4900+2704-7280\times (-0.5)\\\\x^2=7604+3640\\\\x^2=11244\\\\x=\sqrt{11244}\\\\x=106.03

So, c = x= 106.03 mi.

Hence, distance between the ships to the nearest miles = 106.03 ≈ 106 mi.


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