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Mars2501 [29]
1 year ago
6

Can you please help me list the forms As_,_ and limits

Mathematics
1 answer:
Anastasy [175]1 year ago
3 0

Given the function:

f(x)=\frac{2x+1}{x}

First, the graph of the function will be as shown in the following figure:

For the given rational function, we will find the following:

Domain = ( -∞, 0 ) ∪ ( 0, ∞ )

Range = ( -∞, 2) ∪ (2, ∞ )

Increasing = Φ

Decreasing = ( -∞, 2) ∪ (2, ∞ )

All asymptotes:

Vertical asymptote: x = 0

Horizontal Asymptote: y = 2

All limits:

\begin{gathered} \lim _{x\rightarrow-\infty}f(x)=2 \\ \lim _{x\rightarrow\infty}f(x)=2 \\ \lim _{x\rightarrow0^-}f(x)=-\infty \\ \lim _{x\rightarrow0^+}f(x)=\infty \end{gathered}

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What is the least common denominator for the fractions 56and38?
maw [93]

Answer:

The least common factor is 18

Step-by-step explanation:

  • what you need to do is subtract 56 - 38 = 18
  • It would 56/18 and 36/18

  • Hope this helps
  • Hope this is right
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7 0
3 years ago
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Which of the following equals 140 to nearest 10
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<span>Which of the following equals 140 to nearest 10 
A.134 

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3 years ago
3x+4/5=7-2x Please tell me man
jekas [21]

Answer:

Exact Form:

x = 31/25

Decimal Form:

x = 1.24

Mixed Number Form:

x = 1  6/25

Step-by-step explanation:

Hope this helps

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3 years ago
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The ordered pair (−3,−6) is a solution for the first equation, and it is a solution for the second equation. Therefore, (−3,−6)​
Alisiya [41]
False. If x=-3 and y=-6 and you substitute them into the equation they do not add up

7 0
3 years ago
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A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
3 years ago
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