Given data:
The given figure.
The major arc angle is 300 degree, it means the minor arc angle is 60 degree, so the triangle inscribed in the circle is equilateral triangle.
The expression for the area of the shaded region is,
![\begin{gathered} A=\frac{60^{\circ}}{360^{\circ}}(\pi)(7)^2-\frac{\sqrt[]{3}}{4}(7)^2^{} \\ =\frac{1}{6}(\pi)(7)^2-\frac{\sqrt[]{3}}{4}(7)^2 \\ =25.65-21.22 \\ =4.43 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cfrac%7B60%5E%7B%5Ccirc%7D%7D%7B360%5E%7B%5Ccirc%7D%7D%28%5Cpi%29%287%29%5E2-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B4%7D%287%29%5E2%5E%7B%7D%20%5C%5C%20%3D%5Cfrac%7B1%7D%7B6%7D%28%5Cpi%29%287%29%5E2-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B4%7D%287%29%5E2%20%5C%5C%20%3D25.65-21.22%20%5C%5C%20%3D4.43%20%5Cend%7Bgathered%7D)
Thus, the area of the shaded region 4.43 sq-units.
Total = Principal * (1 + rate)^years
Total = 7,100 * (1 + .0775)^30
Total = 7,100 *
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9.3868172981
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Total =
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66,646.40
Source:
http://www.1728.org/compint.htm
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Answer:
2 square root 5
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The equation of the circle is equal to

where
(h,k) is the center and r is the radius of the circle
In this problem we have
center at (0,0) and radius equal 6 units
so

Remember that
If a point lie on the circle, then the point must satisfy the equation of the circle
Substitute the x-coordinate of point Q in the equation of the circle and solve for the y-coordinate of point Q
For x=4


simplify

The point Q lie on the first Quadrant (see the picture)
The y-coordinate is positive
therefore
The y-coordinate of point Q is 
Answer:
-15/4 or -3.75
Step-by-step explanation:
Answer:
D. 5/6 and 10/12
Step-by-step explanation: