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1 year ago

10) Chris invested $5,500. The investment had a simple interest rate of 3.5%. If he plans to leave the

Mathematics

1 answer:

Oksi-84 [34.3K]1 year ago

5 0

Chris will have $7810 at the end of 12 years in his account if the simple interest rate is 3.5%.

According to the question,

We have the following information:

Chris invested $5,500. The investment had a simple interest rate of 3.5%. And he plans to leave the investment alone for 12 years.

Now, we know that the following formula is used to find the simple interest on an investment:

Interest = principal*rate*time/100

Principal = $5500

Rate = 3.5

Time = 12 years

Interest = (5500*3.5*12)/100

Interest = $2310

Now, the total amount in his account will be:

5500+2310

$7810

Hence, Chris will have $7810 at the end of 12 years in his account if the simple interest rate is 3.5%.

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Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that as time increases, the amount of water in the pool increases.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the rate of change (which is also the slope of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

11 gallons per minute

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$

$\implies y-153=11(x-8)$

$\implies y-153=11x-88$

$\implies y=11x-88+153$

$\implies y=11x+65$

When Ann had added no water, x = 0. Therefore,

$y=11(0)+65$

$y=65$

So there was 65 gallons of water in the pool before Ann starting adding water.

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9times 2/3 and than in simplest form

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18/3 then it will be 6

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Let y represent the total cost of publishing a book (in dollars). Let x represent the number of copies of the book printed. Supp

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What is the change in the total cost for each book printed?
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What is the cost to get started (before any books are printed)?
$1250

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2 years ago

Determine whether the sequence converges or diverges. If it converges, find the limit. [Hint:

Zepler [3.9K]

(a) converges; consider the function f(x) = a ˣ, which converges to 0 as x gets large for |a | < 1. Then the limit is 2.

(b) converges; we have

4ⁿ / (1 + 9ⁿ) = (4ⁿ/9ⁿ) / (1/9ⁿ + 9ⁿ/9ⁿ) = (4/9)ⁿ × 1/(1/9ⁿ + 1)

As n gets large, the exponential terms vanish; both (4/9)ⁿ → 0 and 1/9ⁿ → 0, so the limit is 1.

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