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Tresset [83]
1 year ago
10

I really need help. My math teacher doesn't want to help me and isn't responding to my emails. Could you explain how to solve ea

ch of these? Thank you so much!!!

Mathematics
1 answer:
wolverine [178]1 year ago
4 0

4. To determine if a triangle is a right triangle, given that you know the length of its sides, you have to check if its lengths follow the Pythagorean theorem.

This theorem states that the square of the hypothenuse (c) is equal to the sum of the squares of the legs of the triangle (a and b), following the expression:

a^2+b^2=c^2

The triangle is:

We have to check that a²+ b² is equal to c².

The square of the hypothenuse is:

\begin{gathered} c^2=10^2 \\ c^2=100 \end{gathered}

The sum of the squares of the legs of the triangle is:

\begin{gathered} a^2+b^2=8^2+6^2 \\ a^2+b^2=64+36 \\ a^2+b^2=100 \end{gathered}

As you can see, the sum of the squares of the legs of the triangle is 100, which is the same as the square of the hypothenuse. The triangle follows the Pythagorean theorem and can be considered a right triangle.

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Boomer, the dog, eats 3\2​ of dog food each week. How many grams of dog food will Boomer eat in 4weeks?'
sweet [91]

Answer:

6 grams

Step-by-step explanation:

(3/2)*4 = 12/2 = 6

6 0
3 years ago
Read 2 more answers
Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand
dybincka [34]

Answer: Part a) P(a)=\frac{1}{\binom{r+w}{r}}

part b)P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = P(E)=\frac{Favourablecases}{TotalCases}

For part a)

Probability that a red ball is drawn in first attempt = P(E_{1})=\frac{r}{r+w}

Probability that a red ball is drawn in second attempt=P(E_{2})=\frac{r-1}{r+w-1}

Probability that a red ball is drawn in third attempt = P(E_{3})=\frac{r-2}{r+w-1}

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = P(E_{i})=\frac{r-i}{r+w-i}

Thus the probability that events E_{1},E_{2}....E_{i} occur in succession is

P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...

Thus P(E)=\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!

Thus our probability becomes

P(E)=\frac{1}{\binom{r+w}{r}}

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at (r+1)^{th} draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals \binom{r}{r-1}

Thus the probability becomes P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}

Thus required probability of case b becomes P(E)+ P(E_{i})

= P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\

7 0
4 years ago
Can someone pls help
Arisa [49]
c because it just makes sense
3 0
3 years ago
Read 2 more answers
What is 6.5 and 6.55 and -6 and six listed from least to greatest
Mars2501 [29]
-6, 6.5, 6.55. 6
The negative number is way smaller than the others, so its first. Then, 6 is the greatest than the others, so its last and the rest is based on the decimal.
4 0
3 years ago
Please help!! rlly need help
Liono4ka [1.6K]

Answer:

Yes by SAS

Step-by-step explanation:

if you do 42 / 18 you see that the relationship between the sides is 2.3333... so that is one proportional side

Then, you see that there is one angle in both triangles that is 76 degrees, so that is one equal angle

then, you can do 21 / 9 = 2.33333... which is the same as the first proportion which means that is another proportional side.

then you have a side, angle, and a side, so it's SAS

4 0
3 years ago
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