Answer:
40
Step-by-step explanation:
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
Answer:
Step-by-step explanation:
Price of one ticket = $4
Price of t tickets = 4t
1) 4t + 72 > 400
t > (400-72)/4
2) 4t + 72 > 400
4t + 72 - 72 > 400 - 72 {subtract 72 from both sides}
4t > 328
4t/4 > 328/4 {divide both sides by 4}
t > 82
Answer:
x< -0.24
Step-by-step explanation:
So this is going to sound stupid, but I got x< -0.24 which is just not an option, but this is how I got it...
-25x+14>20
subtract 14 from each side
-25x>6
divide each side by -25
x< -0.24
I switch the way the sign was facing bc I divided by a negative.
Now I know that this must be wrong, but it makes the most sense because I am pretty sure I did all of the math right. Sorry this probably didnt help , but I did a lot of work to try and get the right answer, so Im not putting that work to waste
Down payment is 20% of the price of the home. Since the couple saved $35,000, and assuming they will pay the whole money as down payment, the highest priced home they can get is a price whose 20% is $35,000.
We can setup an equation in x (being the price of home) to get the price of the most expensive home they can buy.
<em>Which number (x) , multiplied by 20%, is equal to $35,000?</em>
<em>
</em>
So, the most expensive house they can buy is worth $175,000.
ANSWER: $175,000
Answer:
(a) How many are there to select 2 pairs of gloves?
10 ways
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
130 ways
Step-by-step explanation:
We solve the above questions using Combination
Combination = C(n, r) = nCr
= n!/n! ×(n - r)!
(a) How many are there to select 2 pairs of gloves?
We have 5 pairs of gloves. Therefore, the number of ways to select 2 gloves =5C2
= 5!/2! × (5 - 2)!
= 5!/2! × 3!
= 5 × 4 × 3 × 2 × 1/(2 × 1) × (3 × 2 × 1)!
= 10 ways.
(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)
We are told to select 4 gloves out of the 10 gloves = 10C4
We have 5 pairs, we need to make sure that two out of the selected 4 make a pair = 5 × 2⁴
= 80
Hence,
10C4 - 5C4
= [10!/4! × (10 - 4)!] - 80
= 210 - 80
= 130 ways