You can use ruler and stuff and yea
Answer:
yes
Step-by-step explanation:
Hi there!
We want to see if 9, 40, and 41 can be the sides of a triangle that can exist
We can use triangle inequalities to figure that out
For triangle inequalities, if the lengths of the sides are a, b, and c, then a+b>c, b+c>a, and c+a>b, then the lengths can make a triangle
Let's say that a=9, b=40, and c=41
Now substitute these values into the inequalities:
a+b>c
9+40>41
49>41
This is a true statement.
b+c>a
40+41>9
81>9
This is also a true statement.
41+9>40
50>40
This is a true statement as well.
Since all three of the inequalities ended up being true (all three NEED to be true in order for the given lengths to make a triangle), then we can confirm that 9, 40, and 41 can make a triangle
Hope this helps!
See more on this topic here: brainly.com/question/17357347
Do you mean exponential form as in scientific notation or as in prime factorization.
Now matter I will do both.
As in scientific notation.
200*75
=150*100
=1.5*10000
=1.5*10^4
As in prime factorization.
200*75
=2^3*5^2*3*5^2
=2^3 * 3 * 5^4
Do the one your teacher ask for :) Hope it helps!
Answer:
Coordinate of 4th vertex of the rectangle is ( 8 , -8 ).
Step-by-step explanation:
Given Vertices of Rectangle are ( 5 , -3 ) , ( 5 , -8 ) , ( 8 , -3 )
To find: Coordinate of Fourth Vertex of the rectangle.
First, Plot all given three points on the graph.
Graph is attached.
We know that Opposite sides of the rectangle are equal and parallel.
Also All angles of rectangles are right angle.
So to satisfy these properties of rectangle.
4th coordinate must be on line x = 8 and y = -8.
⇒ Fourth coordinate = ( 8 , -8 )
Therefore, Coordinate of 4th vertex of the rectangle is ( 8 , -8 ).
Answer: Area is 20
Step-by-step explanation:
Perimeter of a rectangle is 24
Let the length be x
Let the breadth be Y
Length is 5times the breadth
I.e
X=5y
Formula for perimeter of a rectangle is
2(length + breadth)
= 2(x+y)
Substitute for x=5y
2(5y+y)=24
2(6y)=24
6y=24/2
6y=12
Y=12/6
Y=2
Breadth = 2
Since length =5y
Length=5(2)
Length = 10
Area of a rectangle = length × breadth
Area= 10×2
Area = 20
Area of the rectangle is 20