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3 years ago

If cos (A+B) = cosAcos B – sinAsin B , find the value of cos 75

Mathematics

1 answer:

kirill [66]3 years ago

4 0

Answer:

Step-by-step explanation:

Cos 75 = Cos ( 30 + 45) {Use Cos (A + B) identity}

= Cos 30*cos 45 - Sin 30 Sin 45

$= \frac{\sqrt{3}}{2}*\frac{1}{\sqrt{2}}-\frac{1}{2}*\frac{1}{\sqrt{2}}\\\\= \frac{\sqrt{3}}{2\sqrt{2}}-\frac{1}{2\sqrt{2}}\\\\=\frac{\sqrt{3}-1}{2\sqrt{2}}\\\\=\frac{(\sqrt{3}-1)*\sqrt{2}}{2\sqrt{2}*\sqrt{2}}\\\\=\frac{\sqrt{3}*\sqrt{2}-\sqrt{2}}{2*2}\\\\=\frac{\sqrt{6}-\sqrt{2}}{4}$

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Solve each system of equations 2x- 5y = 7 3x - y = -9

Darina [25.2K]

Answer:

x = -4; y = -3

Step-by-step explanation:

2x - 5y = 7

3x - y = -9

Rewrite top equation. Multiply both sides of bottom equation by -5. Add equations. This eliminates y, and we solve for x.

2x - 5y = 7

(+) -15x + 5y = 45

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-13x = 52

Divide both sides by -13.

x = -4

Substitute -4 for x in the first original equation and solve for y.

2x - 5y = 7

2(-4) - 5y = 7

-8 - 5y = 7

-5y = 15

y = -3

Answer: x = -4; y = -3

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1. a baker had 10 sacks containing the following amounts of flour: 4 1/2 kg , 31/4 kg ,2 1/2 kg ,2 1/2 kg , 4 kg ,3 1/4 kg ,4 1/

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(a) Derive an equation of the line passing through the points A(0, 545) and B(4, 726). (Let t be the independent variable and y

a_sh-v [17]

Answer:

The equation of the line is $y=45.25t+545$

Step-by-step explanation:

The general for of a line is:

$y=mt+n$ (1)

where:

$m$ is the slope of the line and $m$ is the intercept with the axis of the dependent variable, $y$ in this case.

In order to obtain the value of the slope ( $m$ ) we can use the corresponding slope formula:

$m=\frac{y_{2}-y_1 }{t_2-t_1}$ (2)

where $t_1, t_2, y_1$ and $y_2$ are the corresponding coordinates of the given points. In this case:

$t_1=0\\t_2=4\\y_1=545\\y_2=726\\$

Substituting these values in equation (2) we obtain:

$m=\frac{726-545}{4-0}=\frac{181}{4}=45.25\\m=45.25$

Hence, the line equation is now:

$y=45.25t+n$ (3)

Now to obtain the value of $n$ you can follow two options:

You can substitute one of your points, $A$ or $B$ , in equation (3). In this way, you will obtain an equation where the variable is $n$

Note that for this question, it is easier to select point A because of having the independent variable equals to zero $t=0$ . Hence, substituting point A in equation (3):

$45.25*0+n=545\\n=545$

Therefore, the line equation is: $y=45.25t+545$

The second option to find $n$ is to think of the meaning of the intercept. The intercept of a line is defined as the point in which the line crosses the axis of the dependent variable, which also means that the value of the independent variable for this point is zero. From this, we could have automatically said that $n$ is equal to $545$ .

See the attachment for a plot of the line.

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