Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by (
):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level : 
Two-tailed T-value for df = 63 and
would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be

∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
<span>When order does not matter you use what is called n choose k formula
n!/(k!(n-k)!) where n is the number of things to choose from and k is the number of choices made, in this case:
20!/(4!(20-4)!)=4845</span>
Answer:

Step-by-step explanation:

Answer:
C.
Step-by-step explanation:
Answer:
A
Step-by-step explanation: