The angle of the plane when it rose from the ground is 64.8 degrees
<h3>Application of trigonometry identity</h3>
Given the following parameters from the question
Altitude of the airplane H = 500m
Horizontal distance from airport "d" = 235
Required
angle of elevation
According to the trigonometry identity
tan x = opposite/adjacent
tan x = H/d
tan x = 500/235
tan x = 2.1277
x = arctan(2.1277)
x = 64.8 degrees
The angle of the plane when it rose from the ground is 64.8 degrees
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m<E=45.5 m<F=45.5
this is question 8 can't see question 9
-13 to 0 = 13 degrees changed. 0 to 22 is 22 degrees changed. 13 + 22 = 35 degree change.
10-3 = 7.
So there was a change of 35 degrees across 7 hours
35/7 = 5 degrees per hour.
The GCF of the three terms (9a, -18b and 21c) is 3
Rewrite each of the terms so 3 is a factor
9a = 3*3a
-18b = -3*6b
21c = 3*7c
So we can say...
9a - 18b + 21c = 3*3a - 3*6b + 3*7c
9a - 18b + 21c = 3(3a - 6b + 7c)
Answer: 3(3a - 6b + 7c)
If you distribute outer 3 to each of the inner terms and multiply, you'll get the original expression again.
Here, Function: h(t)= -16t² + 70t + 40
So, put the value of t, (time at which you want to calculate the height)
h(1) = -16(1)² + 70(1) + 40
h(1) = -16 + 110
h(1) = 94
Now, h(2) = -16(2)² + 70(2) + 40
h(2) = -64 + 180
h(2) = 116
h(3) = -16(3)² + 70(3) + 40
h(3) = -144 + 250
h(3) = 106
In short, Your height depends on time, and at each time it would be different, can be expressed by the coordinates on a Graph: (1, 94) (2, 116) (3, 106)
Hope this helps!
