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Diano4ka-milaya [45]
3 years ago
12

HELP MEH HELP MEH PLZ

Mathematics
2 answers:
tatuchka [14]3 years ago
8 0
The answer is the 3rd one you can eliminate the first two because they would be incorrect but if you want to check you answer you can enter the 3rd one on a scientific calculator
bulgar [2K]3 years ago
6 0

Answer:

[2×10*(-3) × (4×10*(4)] = 80

Step-by-step explanation:

First of all 0.002 is 10*(-3) and not 10(-2) , so you can eliminate the first 2 answers.

Second of all, according to the calculator the left equation is correct, while the right one isn't... so there you go

Glad to help :)

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Please answer correctly !!!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!
nydimaria [60]

Answer:

Step-by-step explanation:

The discriminant is what's under the square root sign in the quadratic equation.  The equation for the discriminant is b^{2}-4ac, where b is the coefficient of x, a is the coefficient of x^{2}, and c is the number with no variable attatched to it.  If we plug in the numbers (17^{2} -4*4*3) it gives you 241, which is the discriminant.  Since 241 is more than zero, it has 2 zeros.  If the discriminant was 0, there'd be 1 zero, and less then zero there would be zero zeros.

3 0
3 years ago
State if each scenario involves a permutation or a combination. Then find the number of possibilities.
Drupady [299]
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8 0
2 years ago
Hi, can someone help with this problem ASAP?
Naddika [18.5K]

Answer:

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Step-by-step explanation:

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3 0
2 years ago
Which choice answer is it?
Debora [2.8K]

Your answer would be option (1) -3x² - 18x + 19.

To find this we need to substitute in the G and F expressions into G - 3F and see what the outcome is, as this will give us the answer.

First I’m going to multiply the F expression, 2x² + 6x - 5, by 3:

3 × (2x² + 6x - 5) = 3(2x²) + 3(6x) - 3(5) = 6x² + 18x - 15.

Now we need to subtract this expression from G, which is 3x² + 4, which I will do by term:

3x² - 6x² = -3x²

0x - 18x = -18x

4 - -15 = 19

So therefore overall your answer is -3x² - 18x + 19.

I hope this helps! Let me know if you have any questions :)

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3 years ago
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