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2 years ago

HELP MEH HELP MEH PLZ

Mathematics

2 answers:

tatuchka [14]2 years ago

8 0

The answer is the 3rd one you can eliminate the first two because they would be incorrect but if you want to check you answer you can enter the 3rd one on a scientific calculator

bulgar [2K]2 years ago

6 0

Answer:

[2×10*(-3) × (4×10*(4)] = 80

Step-by-step explanation:

First of all 0.002 is 10*(-3) and not 10(-2) , so you can eliminate the first 2 answers.

Second of all, according to the calculator the left equation is correct, while the right one isn't... so there you go

Glad to help :)

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3 years ago

= 8 cm, height = 67 cm.

zavuch27 [327]

Answer:

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3 years ago

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Fynjy0 [20]

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3 years ago

What much expression represents a rational number?

Pie

Answer:

$\displaystyle \frac{2}{7}+\sqrt{121}$

Step-by-step explanation:

<u>Rational Numbers</u>

A rational number is any number that can be expressed as a fraction

$\displaystyle \frac{a}{b}, \ b\neq 0$

for a and b any integer and b different from 0.

As a consequence, any number that cannot be expressed as a fraction or rational number is defined as an Irrational number.

Let's analyze each one of the given options

$\displaystyle \frac{5}{9}+\sqrt{18}$

The first part of the number is indeed a rational number, but the second part is a square root whose result cannot be expressed as a rational, thus the number is not rational

$\pi + \sqrt{16}$

The second part is an exact square root (resulting 4) but the first part is a known irrational number called pi. It's not possible to express pi as a fraction, thus the number is irrational

$\displaystyle \frac{2}{7}+\sqrt{121}$

The square root of 121 is 11. It makes the whole number a sum of a rational number plus an integer, thus the given number is rational

$\displaystyle \frac{3}{10}+\sqrt{11}$

As with the first number, the square root is not exact. The sum of a rational number plus an irrational number gives an irrational number.

Correct option:

$\boxed{\displaystyle \frac{2}{7}+\sqrt{121}}$

6 0

2 years ago

The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 199 times. Here are the observed

Anton [14]

Answer with explanation:

An Unbiased Dice is Rolled 199 times.

Frequency of outcomes 1,2,3,4,5,6 are=28, 29, 47, 40, 22, 33.

Probability of an Event

$=\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(1)=\frac{28}{199}\\\\P(2)=\frac{29}{199}\\\\P(3)=\frac{47}{199}\\\\P(4)=\frac{40}{199}\\\\P(5)=\frac{22}{199}\\\\P(6)=\frac{33}{199}\\\\\text{Dice is fair}\\\\P(1,2,3,4,5,6}=\frac{33}{199}$

→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value

$(e_{1})^2=(P_{1})^2+(P'_{1})^2\\\\(e_{1})^2=[\frac{28}{199}]^2+[\frac{33}{199}]^2\\\\(e_{1})^2=\frac{1873}{39601}\\\\(e_{1})^2=0.0472967\\\\e_{1}=0.217478\\\\z_{1}=\frac{P'_{1}-P_{1}}{e_{1}}\\\\z_{1}=\frac{\frac{33}{199}-\frac{28}{199}}{0.217478}\\\\z_{1}=\frac{5}{43.27}\\\\z_{1}=0.12$

→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.

$(e_{2})^2=(P_{2})^2+(P'_{2})^2\\\\(e_{2})^2=[\frac{29}{199}]^2+[\frac{33}{199}]^2\\\\(e_{2})^2=\frac{1930}{39601}\\\\(e_{2})^2=0.04873\\\\e_{2}=0.2207\\\\z_{2}=\frac{P'_{2}-P_{2}}{e_{2}}\\\\z_{2}=\frac{\frac{33}{199}-\frac{29}{199}}{0.2207}\\\\z_{2}=\frac{4}{43.9193}\\\\z_{2}=0.0911$