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1 year ago

Find the value of x in the triangle shown below: 2.5 6.5 Choose 1 answer: I =6 3 = V48.5 x = 9 x = V9

Mathematics

1 answer:

Andreyy891 year ago

4 0

Answer:

x = 6 units

Step-by-step explanation:

We know that, By pythagoras theorem,

Hypotenuse2 = base2 + perpendicular2

Given, Hypotenuse = 6.5

perpendicular = 2.5

base = x

So, by putting the values,

6.52 = 2.52 + x2

42.25 = 6.25 + x2

36 = x2

Hence, x = 6 units

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Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago

One gallon of gasoline in buffalo, New York costs $2.29. In Toronto, Canada, one liter of gas costs $0.91. There are 3.8 liters

Solnce55 [7]

Answer:

The cost of one gallon of gas in Toronto, Canada is $3.458.

Solution:

Given, One gallon of gasoline in buffalo, New York costs $2.29.

In Toronto, Canada, one liter of gas costs $0.91.

There are 3.8 liters in one gallon.

We have to find how much does one gallon of gas cost in Toronto?

Now, cost of one gallon of gas in Toronto = cost of one litre of gas in Toronto x 3.8 liters for 1 gallon.

Cost of one gallon of gas = 0.91 x 3.8 = 3.458

Hence, the cost of one gallon of gas in Toronto, Canada is $3.458.

3 0

3 years ago

I need the answer for this exact question

denis23 [38]

Answer:

$y=\frac{7}{2}x-20$

Step-by-step explanation:

Let the equation of the line be $y-y_1=m(x-x_1)$ where, 'm' is its slope and $(x_1,y_1)$ is a point on it.

Given:

The equation of a known line is:

$y=-\frac{2}{7}x+9$

A point on the unknown line is:

$(x_1,y_1)=(4,-6)$

Both the lines are perpendicular to each other.

Now, the slope of the known line is given by the coefficient of 'x'. Therefore, the slope of the known line is $m_1=-\frac{2}{7}$

When two lines are perpendicular, the product of their slopes is equal to -1.

Therefore,

$m\cdot m_1=-1\\m=-\frac{1}{m_1}\\m=-\frac{1}{\frac{-2}{7} }=\frac{7}{2}$

Therefore, the equation of the unknown line is determined by plugging in all the given values. This gives,

$y-(-6))=\frac{7}{2}(x-4)\\y+6=\frac{7}{2}x-14\\y=\frac{7}{2}x-14-6\\\\y=\frac{7}{2}x-20$

The equation of a line perpendicular to the given line and passing through (4, -6) is $y=\frac{7}{2}x-20$ .

3 0

3 years ago

Jones assembles 200 relays in the same time that Smith assembles 180. When Jones has completed 300 relays, how many will Smith h

Finger [1]

Answer:

270

Step-by-step explanation:

Jones turns out 200 relays to Smith's 180. You set up that basic ratio and make a proportion out of it.

S/J = 180/200

Now you make your proportion

S/J = x/300

But the 2 ratios much remain the same.

180/200 = x / 300 Multiply both sides by 300

180*300/200 = x Multiply the numerator together.

54000/200 = x Do the division

270 = x

Smith will have turned out 270 relays.

4 0

3 years ago

A mail-order supplier of small electrical parts charges a shipping fee of $8, plus $5 for each pushbutton light switch ordered.

azamat

$38 in total including shipping fee

7 0

3 years ago