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EastWind [94]
2 years ago
14

Which equation represents the relationship in the table?

Mathematics
1 answer:
Akimi4 [234]2 years ago
3 0
D) y=14-5x
Hope this helps!
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An expression is shown.<br>2 3/4 x 2/3<br>What is the value of the expression?​
Novay_Z [31]

Answer:

The answer is 1 5/6

Step-by-step explanation:

5 0
3 years ago
What is the simplify answer to 4 3/5 + 15 ÷ 1/5 =​
Tasya [4]

Answer:

79.6

Step-by-step explanation:

4 3/5+15÷1/5

23/5+15÷1/5

4.6+15÷0.2

4.6+75

79.6

6 0
3 years ago
Drag each number to the correct location on the table.
ASHA 777 [7]

Answer:

\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}

          3\sqrt{25}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \sqrt{141}\\\\\sqrt{256} \\\\1. \overline{ 1625} \\\\\frac{-11}{151}

Step-by-step explanation:

Since we believe it  

The number sequence is that those which can be described as \frac{p}{q} and that is not ending and recurring.  Figures that are unreasonable are also the ones, that are not \frac{p}{q} and therefore are non-ending, non-recurring.  

The number sequence is 3\sqrt{25} = 3 \times 5 = 15

Rational amount since it is classified as \frac{p}{q}  .\frac{-11}{151} is really a rational number.  

1.\overline{1.625} is a real function, since it does not end but repeats it.  

The rational number \sqrt {256} = 16

Unreasonable number \sqrt{141}.

7 0
3 years ago
Read 2 more answers
Divide 88,800 By 100 Explain the shift of the digits and the change in the value of each digit
ololo11 [35]
88,800÷100=888 because when you are dividing by multiples of 10, the place value always move over to the right depending on how many digits there are.

6 0
4 years ago
Galena is solving the following system. 3x+2y+3z =5 7x+y +7z=-1 4x-4y-z=-3
babymother [125]

Answer:

She did not multiply equation 3 in step 2 by the correct value.

Step-by-step explanation:

Given:

3x+2y+3z=5\\7x+y+7z=-1\\4x-4y-z=-3

In order to solve this, we need to eliminate any one variable and then form a simultaneous equation with the remaining two variables. Then, we nee to solve the simultaneous equation.

Here, Galena is trying to eliminate the variable z first.

Step 1:  She multiplies equation (3) by 3 and adds it to equation (1)

Let us multiply equation (3) by 3

(4x-4y-z=-3)\times 3 = (3\times 4x)-(3\times 4y)-(3\times z)=3\times -3\\(4x-4y-z=-3)\times 3 =12x-12y-3z=-9

Now, adding this to equation 1 will cancel out z terms.

12x-12y-3z+3x+2y+3z=-9+5\\(12x+3x)+(-12y+2y)+(3z-3z)=-4\\15x-10y+0=-4

Now, she need to make one more equation in x\ and \ y.

Step 2: She multiplies equation (3) by -7 and adds it to equation (2)

Multiplying equation (3) by -7 will give,

(4x-4y-z=-3)\times -7 = (-7\times 4x)-(-7\times 4y)-(-7\times z)=-7\times -3\\(4x-4y-z=-3)\times 3 =-28x+28y+7z=21

Now, adding this to equation 2 will not cancel out z terms.

-28x+28y+7z+7x+y+7z=21-1\\(-28x+7x)+(28y+y)+(7z+7z)=20\\-21x+29y+14z=20

So, she makes mistake in step 2 as the z terms are not being cancelled.

6 0
3 years ago
Read 2 more answers
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