Answer:
The dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
Step-by-step explanation:
The formula for the perimeter of a rectangle = 2(L + W)
= 2L + 2W
The perimeter = 46 mm
L = 3x + 3
W = x - 4
P = 2L + 2W
46mm = 2(3x + 3) + 2(x - 4)
46 = 6x + 6 + 2x - 8
Collect like terms
46 +8 -6 = 6x + 2x
48 = 8x
x = 48/8
x = 6
Since the Length = 3x + 3
= 3(6) + 3
= 18 + 3
= 21mm
Since the Width = x - 4
= 6 - 4
= 2mm
Therefore, the dimension of this rectangle = 2mm by 21mm
Where 2 mm = Width of the rectangle
21 mm = Length of the rectangle.
Answer:
1. 18.85in
4. 25.13m
Step-by-step explanation:
I got you
So to find the circumference of any circle we use the equation 2pi(r)
2(3.1415)(3)= 18.85in for the first one because radius is half of the diameter which is 6 so half of 6 is 3
For 4. 4m is actually the radius so just plug that into the equation 2pi(4)=25.13m
Answer:
it is
Step-by-step explanation:
0.75. or that's at least what Google told me
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
