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3 years ago

6

Evaluate 8x for each value of x x=0.5

1 answer:

r-ruslan [8.4K]3 years ago

4 0

The answer is 4 because 8*.5=4 or you can also think of is at 8*1/2=4. Hope this helped!

You might be interested in

Whats 126/399 in its simplest form

marusya05 [52]

A common factor of both 126 and 399 is 3 so we can divide both numbers by 3.

126 / 3 = 42
399 / 3 = 133

A common factor for both 42 and 133 is 7 so we can divide both numbers by 7.

42 / 7 = 6
133 / 7 = 19

19 is a prime number so we can't reduce it anymore, therefore 126/399 in its simplest form is 6/19

4 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Is 272 oz greater than 20 lb

Karolina [17]

We know that 1 lb = 16 oz
So lets convert the 20 lb to oz and then compare the two quantities in consistent units.
If 1 lb = 16 oz then 20 lb are equal to 20*16 oz, that is
20 lb = 20*16 oz = 320 oz
therefore,
320 oz are greater than 272 oz, or,
20 lb are greater that 272 oz

3 0

3 years ago

Help finding answer

ratelena [41]

the answer for this question is cot theta is equal to 24/ 7

7 0

3 years ago

If xy + 12 = 6x + 7, find y if x =5.

Igoryamba

Answer: look at the picture

Step-by-step explanation: Hope this help :D

4 0

3 years ago

Read 2 more answers