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2 years ago

Evaluate 8x for each value of x x=0.5

Mathematics

1 answer:

r-ruslan [8.4K]2 years ago

4 0

The answer is 4 because 8*.5=4 or you can also think of is at 8*1/2=4. Hope this helped!

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What is the area enclosed by the curves???

slava [35]

The x and y axis
i think

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2 years ago

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Colleen is making raffle tickets for the school's give-away drawing. She wants to use the digits 2, 5, and 7 to make three-digit

daser333 [38]

Answer:

You can make 9 three Digit numbers

Step-by-step explanation:

The 9 three digit numbers are:

257

275

752

725

527

572

This can also be easily found out by multiplying the number of digits to the number of digits needed for the number, in this case, there are 3 digits, and the number must have 3 digits in them (without them repeating).

3 digits x 3 needed for the numbers = 9 three digit numbers

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2 years ago

5 more than 3 times a variable, x, is 23

Monica [59]

3x + 5 = 23

5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23

(you add 5 to 3x)

If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:

3x + 5 = 23 Subtract 5 on both sides

3x + 5 - 5 = 23 - 5

3x = 18 Divide 3 on both sides to get "x" by itself

$\frac{3x}{3} =\frac{18}{3}$

x = 6

5 0

3 years ago

If i have 100 gummy vitamins and i take two a day how many months would they last me?

never [62]

100 vitamins/2 a day=50 days 50 days/30 days in a month (assumedly)= 5/3 months 1.66

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2 years ago

Please math , help

Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

$M = \frac{199+204+201+197+195+204+200}{7} = 200$

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

$S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18$

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

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2 years ago