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1 year ago

For the arithmetic sequence 42, 32, 22, 12... find the 5th, 6th, and 7th terms

1 answer:

vladimir2022 [97]1 year ago

6 0

Notice that the sequence involves subtracting 10 units from the previous term. Then, we are in the case of an arithmetic sequence with common difference = -10, since we build the next rem by subtracting 10 from the previous. so we have:

term 1 = 42

term 2 = 42 - 10 = 32

term 3 = 32 - 10 = 22

term 4 = 22 - 10 = 12

term 5 = 12 - 10 = 2

term 6 = 2 - 10 = -8

term 7 = -8 - 10 = -18

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9+(-2)x3=7x3 DONT forget pemdas or gemdas

gizmo_the_mogwai [7]

Answer:

The equation is true.

Step-by-step explanation:

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4 years ago

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svetoff [14.1K]

Answer:

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Step-by-step explanation:

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3 years ago

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Bingel [31]

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3 years ago

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Julli [10]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A car had a value of $10,000 and depreciates at a rate of 7% a year. What is the cars value after 3 years.

SOVA2 [1]

Answer:

Step-by-step explanation:

The exponential decay function is

$v(t)=a(b)^t$ where a is the initial value of the car, b is the rate of decay, and t is the time in years. Our rate of decay can also be written as (1 - r) where r is the depreciation in decimal form. Our equation looks like this:

$v(t)=10000(1-.07)^t$ which simplifies to

$v(t)=10000(.93)^t$ Now we can solve our problem for any number of years you'd like. We've been tasked to find the value of the car after 3 years, so:

$v(t)=10000(.93)^3$ which simplifies a bit to:

$v(t)=10000(.804357)$ so

v(t) = 8043.57

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3 years ago