Question

For the arithmetic sequence 42, 32, 22, 12... find the 5th, 6th, and 7th terms

Answer 1

Notice that the sequence involves subtracting 10 units from the previous term. Then, we are in the case of an arithmetic sequence with common difference = -10, since we build the next rem by subtracting 10 from the previous. so we have:

term 1 = 42

term 2 = 42 - 10 = 32

term 3 = 32 - 10 = 22

term 4 = 22 - 10 = 12

term 5 = 12 - 10 = 2

term 6 = 2 - 10 = -8

term 7 = -8 - 10 = -18