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ohaa [14]
2 years ago
8

1. Find the value of x to the nearest tenth.

Mathematics
1 answer:
Lunna [17]2 years ago
7 0

Step-by-step explanation:

1.

a perpendicular line on a chord of a circle going through the center of the circle splits the chord in half.

so, x is 2 times the missing leg of the right-angled triangle. and we are using Pythagoras :

c² = a² + b²

c being the Hypotenuse (the baseline opposite of the 90° angle).

so,

8² = 3² + (x/2)²

64 = 9 + x²/4

55 = x²/4

220 = x²

x = 14.83239697... ≈ 14.8

2.

I assume x is again the length of the whole chord (the diagram is not really clear in that regard).

the chord length using the distance from the center of the circle is

2 × sqrt(r² - d²)

r being the radius, d being the perpendicular distance from the center.

remember, the radius is half the diameter.

so, in our case

2 × sqrt ((12/2)² - 3²) = 2 × sqrt(36 - 9) = 2×sqrt(27) =

= 10.39230485... ≈ 10.4

3.

c is the supplementary angle to 76°, as the baseline of the abd triangle is the diameter of the circle, so c+76 are a half-circle.

c = 180 - 76 = 104°

the circle theorem says, the angle at the center is twice the angle at the circumference.

so,

a = 76/2 = 38°

similarly,

b = 104/2 = 52°

and

d = 180 - 38 - 52 = 90°

as it must be, as any inscribed triangle over the diameter of a circle must be right-angled.

4.

like in 3.

c = 150/2 = 75°

a + 90 + 150 = 360 (as together they are a full circle)

a = 360 - 90 - 150 = 120°

as a is the arc angle of the chord, it is also the inner angle at the center point of the triangle chord-center.

this triangle is an isoceles triangle (both invisible legs and therefore also both angles to the baseline are the same).

the sum of all angles in a triangle is 180°.

so, both leg angles of that triangle are

(180 - 120)/2 = 60/2 = 30°

b is the complementary angle to 30°, as this outside line is the tangent to the circle at the chord end (at a right angle to the triangle leg).

so,

b = 90 - 30 = 60°

5.

similar to 4.

x + 95 + 72 = 360

x = 360 - 95 - 72 = 193°

and for y let's consider the tangent secant angle theorem :

y = (arc angle of "outside" arc - arc angle of "inside"arc)/2

y = (193 - 72)/2 = 121/2 = 60.5°

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In 2014, Chile experienced an intense earthquake with a magnitude of 8.2 on the Richter scale. In 2010, Haiti also experienced a
serg [7]

Answer:

The intensity of the earthquake in Chile was about 16 times the intensity of the earthquake in Haiti.

Step-by-step explanation:

Given:

magnitude of earthquake in Chile =  8.2

magnitude of earthquake in Haiti = 7.0

To find:

Compare the intensities of the two earthquakes

Solution:

The magnitude R of earthquake is measured by R = log I

R is basically the magnitude on Richter scale

I is the intensity of shock wave

For Chile:

given magnitude R of earthquake in Chile =  8.2

R = log I

8.2 = log I

We know that:

y = log a_{x}  is equivalent to: x = a^{y}  

R = log I

8.2 = log I becomes:

I = 10^{8.2}

So the intensity of the earthquake in Chile:

I_{Chile}  = 10^{8.2}

For Haiti:

R = log I

7.0 = log I

We know that:

y = log a_{x}  is equivalent to: x = a^{y}  

R = log I

7.0 = log I becomes:

I = 10^{7.0}

So the intensity of the earthquake in Haiti:

I_{Haiti}  = 10^{7}

Compare the two intensities :

\frac{I_{Chile} }{I_{Haiti} } }

= \frac{10^{8.2} }{10^{7} }

= 10^{8.2-7.0}

= 10^{1.2}

= 15.848932

Round to the nearest whole number:

16

Hence former earthquake was 16 times as intense as the latter earthquake.

Another way to compare intensities:

Find the ratio of the intensities i.e. \frac{I_{Chile} }{I_{Haiti} } }

log I_{Chile} - log I_{Haiti} = 8.2 - 7.0

log(\frac{I_{Chile} }{I_{Haiti} } }) = 1.2

Convert this logarithmic equation to an exponential equation

log(\frac{I_{Chile} }{I_{Haiti} } }) = 1.2

10^{1.2} = \frac{I_{Chile} }{I_{Haiti} } }

Hence

\frac{I_{Chile} }{I_{Haiti} } }  = 16

6 0
2 years ago
REALLY NEED HELP!!!<br> see picture*****
vladimir1956 [14]

Answer:

11) r=4

12) z_3+z_1=A

13a) \bar z_1=3-2i and \bar z_2=-5+3i

13b)  \bar {z_1z_2}=-9-19i

Step-by-step explanation:

11. The given equation in rectangular coordinates is x^2+y^2=16

To convert to polar form, use the relation x^2+y^2=r^2

This implies that:

\implies r^2=16

r=\sqrt{16}

r=4

In polar coordinates, r=4 is a circle with radius 4 units.

12.  From the diagram;

z_3=-3-3i

z_2=1+i

z_1=4+i

A=1-2i

We can see that two arrows are moving in anticlockwise direction to meet A which is moving in the clockwise direction;

\implies (-3-3i)+(4+i)=1-2i

\therefore z_3+z_1=A

13. The conjugate of the complex number: z=a+bi is \bar z=a-bi

Part a) The given complex numbers are:

z_1=3+2i and z_2=-5-3i

The conjugates of these complex numbers are:

\bar z_1=3-2i and \bar z_2=-5+3i

Part b) The product of z_1=3+2i and z_2=-5-3i is

z_1z_2=(3+2i)(-5-3i)

z_1z_2=-15-9i-10i-6i^2

z_1z_2=-9-19i

The conjugate of the product is:

\bar {z_1z_2}=-9-19i

5 0
3 years ago
Please help asap !!
Ivan

Answer:

triangle abc = acb

Step-by-step explanation:

ist right answer of this test

5 0
3 years ago
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VashaNatasha [74]

Answer:

30

Step-by-step explanation:

You can use the triangle area theorem-

15x4(/2)=30

4 0
1 year ago
The art teacher needs 70 markers for her classes. The markers come in packages of 15. How many packages of markers will the art
Temka [501]

Answer:

5

Step-by-step explanation:

Take the number of markers and divide by the number in each package

70/15

4.6666repeating

Round to the nearest whole number to determine the number of packages

5

They will need to buy 5 packages

5 0
3 years ago
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