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dem82 [27]
1 year ago
13

According to the graph, what is the factorization of x - 5x + 6? y=x2.5x + 6 5 A. (x - 3)(x-2) B. (x+3)(x - 2) C. (x-3)(x + 2) O

D. (x + 3)(+ 2) E PREVIOUS

Mathematics
1 answer:
8_murik_8 [283]1 year ago
6 0

Given:

To find the factorization of the graph,

x^2-5x+6

By factorization, we get

\begin{gathered} x^2-2x-3x+6 \\ x(x-2)-3(x-2) \\ (x-3)(x-2) \end{gathered}

Hence option a) is the correct answer.

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11. If f(x)=4x-9, what is the equation for f^-1(x)?
FrozenT [24]
F(x) = 4x - 9

let f(x) = y, this implies that  x = f⁻¹(y)

y = 4x - 9           Let us solve for x.

4x - 9 = y

4x = y + 9

x = (y + 9)/4

Recall that x = f⁻¹(y),

x = (y + 9)/4

f⁻¹(y) = (y + 9)/4

That means that for f⁻¹(x)

f⁻¹(x) = (x + 9)/4

Hope this explains it.
3 0
3 years ago
Which numbers represents a repeating decimal -2/5, -7, 3/9, 11/12
Olegator [25]
-2/5=-.4
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6 0
4 years ago
Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
Helen is preparing candy bags for the children at a party. she has 12 flavors of lollipops, 4 types of candy bars, and 6 flavors
castortr0y [4]
Your answer would be 48
3 0
2 years ago
What is the rate of change for f(x) = 4 sin x − 2 on the interval from x = 0 to x = pi over 2? pi over 4 4 over pi pi over 8 8 o
MaRussiya [10]
Hello,
f(π/2)=4*sin(π/2)-2=4*1-2=2
f(0)=4*sin(0)-2=0-2=-2

rate=(2+2)/(π/2-0)=8/π
Answer D
3 0
3 years ago
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