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arlik [135]
4 years ago
13

Plzzzzzzzzzzzzzzzzz help quick

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
3 0

Answer:

y=-2x-7 D

Step-by-step explanation:

You might be interested in
Find the error in the following sample of work, if one exists.
ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

<u>Line 1:</u>

In line 1, the equation is given and is completely fine.

y^{2}+8xy+2y+16x=0

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

<u>Line 2:</u>

In line 2, the terms are grouped, from which we can factor out common terms.

(y^{2}+8xy)+(2y+16x)=0

This is also fine.

<u>Line 3:</u>

In line 3, the common term y is taken out from group 1 and 2 from other group.

y(y+8x)+2(y+8x)=0

which is exactly what is given in line 3.

<u>Line 4:</u>

In line 4 the common factors can be seen and easily split into 2 factors.

(y+2)(y+8x)=0

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0
3 years ago
Expand and simplify 2(a+3)+3(2a-1)
AlexFokin [52]
2(a+3)+3(2a-1)
=2a+6+6a-3
=8a+3

7 0
4 years ago
5х – 2 = 3х + 4 sove equation for x​
Kazeer [188]

Answer:

x=3

Step-by-step explanation:

5х - 2 = 3х + 4

5х - 3х = 4 + 2

2х = 6

х = 6/2

х = 3

Hope this helps!

8 0
3 years ago
Read 2 more answers
First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia
RUDIKE [14]

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, \frac{336}{3.728} = 90.37 ≈ 90 such patches can be made out of the whole material. (Answer)

3 0
3 years ago
What is the factorization of the trinomial below?x3 - 12x2 + 35x?
Fed [463]
X³ - 12x² + 35x

x(x² - 12x + 35)

x(x-5)(x-7)
4 0
4 years ago
Read 2 more answers
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