Ask question

Ask question

All categories

2 years ago

12

A tank has dimensions of 12m x 8m x 5 meters using an iron sheet. The tank is open at the top. If the sheet is 4m wide, what is

the length of the sheet

2 answers:

Salsk061 [2.6K]2 years ago

6 0

Answer:Length if tank=12m

Step-by-step explanation:

Dimension of tank is 12m by 8m by 5m

Which is length × breadth × heigh

kicyunya [14]2 years ago

6 0

Answer: 74m

Step-by-step explanation: Area of sheet required for making the tank = total surface area of tank with one top open, this is

L×b+2(L×h+b×h)=12×8+2(12×5+8×5)=296m.

B of sheet =4m

L×B=296

B=4m already given.

L=296/4=74m

Length of sheet =74m

You might be interested in

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

2 years ago

If m ABC = 122°, and m<br> then m

ANTONII [103]

Answer:

m < DBC = 51

Step-by-step explanation:

Looking at the picture, we know <ABD and <DBC make up <ABC. Knowing this, we can set up an equation like so, plug in the known values, and solve to find m<DBC:

$m$

6 0

2 years ago

Graph the function y=4(x-3)^2

bagirrra123 [75]

Answer:

Step-by-step explanation:

4 0

3 years ago

Select the best answer to complete the sentence. A Rigid Motion or Isometry ______________________.

Dmitry_Shevchenko [17]

Answer: A. preserves length, angle measures and distance between points

Rigid motions or isometries are any of the three transformations below

translation (aka shifting)
rotation
reflection

Any of those three transformations will keep the figure the same size and shape. That means distances between any two points are kept the same, and angle measures are kept the same as well. Everything is kept the same. The only difference is that the figure is in a different location, is rotated somehow, or it is reflected some way. You can use a series of transformations to undo everything to get the original figure back.

If you wanted to change the size of the figure, then you would apply dilation, which isn't an isometry.

5 0

2 years ago

| x-3 | < x-3<br><br> can someone give a step by step process on how to do this?

statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)

2. Solve each equation separately

(a) Equation (1)

$\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}$

(b) Equation (2)

$\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &$

For example, if x = 0, we get

|0 - 3| < 0 - 3 or

3 < -3

4 0

3 years ago