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iragen [17]
1 year ago
10

If m<9=130°, what is m<4?

Mathematics
1 answer:
nikklg [1K]1 year ago
3 0

From the diagram provided, the two lines that are left and right of each other are parallel and are cut by a transversal. That means,

\begin{gathered} \angle9=\angle5\text{ (corresponding angles are equal)} \\ \text{Similarly,} \\ \angle8=\angle4\text{ (corresponding angles are equal)} \end{gathered}

If angle 9 equals 130, then angle 8 equals,

\begin{gathered} 130+\angle8=180\text{ (angles on a straight line sum up to 180)} \\ \angle8=180-130 \\ \angle8=50 \end{gathered}

If angle 8 equals angle 4, then angle 4 equals 50 degrees

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Find the product. (-3/5) (2/9)
ivann1987 [24]

Answer:

-0.13333333333

6 0
2 years ago
Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides?
Yuri [45]

Answer:

Option D. AC= 10 cm and CE= 5 cm

Step-by-step explanation:

From the given figure two triangles ΔABC and ΔADE are similar and two lines BC║DE.

From these similar triangles we know

\frac{AB}{AD}=\frac{BC}{DE}=\frac{AC}{AE}

\frac{8}{12}=\frac{BC}{9}=\frac{AC}{AE}

Therefore \frac{AC}{AE}=\frac{8}{12}=\frac{2}{3}

Or AC=\frac{2}{3}AE

Now from pythagoras theorem

AE = √(AD²+ED²) = √(12²+9²) = √(144+81) =√225 = 15 cm

Since we know side AC = \frac{2}{3}AE

                                        = \frac{2}{3}\times 15

                                        = 10 cm

Therefore AC = 10 cm and AE = 15cm and CE = (15-10) = 5 cm


8 0
3 years ago
Help please!!!
katovenus [111]

Answer:

x = \frac{7+\sqrt{47}\times i }{4}

Step-by-step explanation:

<u>To solve quadratic systems,we always substitute one variable in terms if the other and then solve the equation.</u>

x + 2y = 6                                 ---------------(1)

y - 5 = (x-2)^{2}         ---------------(2)

y = (x-2)^{2} + 5         ---------------(3)

Substitute (3) in (1) ,

x + 2( (x-2)^{2} + 5 ) = 6

(a + b)^{2} =a^{2} + 2ab + b^{2}

x + 2( x^{2} - 4x + 4 + 5 ) = 6

2x^{2} - 7x + 12=0      --------------(4)

The roots of the quadratic equation ax^{2}  +bx+c is

x = \frac{(-b) + \sqrt{(-b)^{2}-4 \times ac }  }{2 \times a}  -----------(5)

According to equation (5),solution of (4) is

x =  \frac{7 + \sqrt{(-7)^{2}-4 \times 24 }  }{2 \times 2}

x =  \frac{7+\sqrt{49-96}}{4}

x = \frac{7+\sqrt{47}\times i }{4}

 

4 0
3 years ago
Me Henderson has 2 bouncy-ball vending machines. He buys one bag of the 27-millimeter balls and one bag of the 40- millimeter ba
serious [3.7K]
20 bouncy balls in each machine
7 0
3 years ago
What are the first four terms if the sequence represented by the expression n (n-1) -4?
shepuryov [24]
We have that
<span>n (n-1) -4

for n=1
a1=1*(1-1)-4------> a1=-4

for n=2
</span>a2=2*(2-1)-4------> a2=-2

for n=3
a3=3*(3-1)-4------> a3=2

for n=4
a4=4*(4-1)-4------> a4=8

the answer is
-4,-2, 2, 8
5 0
3 years ago
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